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anonymous
 5 years ago
Consider the graph defined by
http://www.webassign.net/cgibin/symimage.cgi?expr=y%20%3D%20%28x%20%205%29%2F%28x%20%206%29
(a) Use the definition of the derivative to find the slope of the tangent line to the graph at the point (7, 2).
slope =
(b) Find an equation of the tangent line to the graph at the point (7, 2).
y =
anonymous
 5 years ago
Consider the graph defined by http://www.webassign.net/cgibin/symimage.cgi?expr=y%20%3D%20%28x%20%205%29%2F%28x%20%206%29 (a) Use the definition of the derivative to find the slope of the tangent line to the graph at the point (7, 2). slope = (b) Find an equation of the tangent line to the graph at the point (7, 2). y =

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont use the definition, cheat and use the quotient rule

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0how do i reach these kids

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok you write it out myininaya lets see you write this in latex using the definition. i will wait...

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i cant scan it in? :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me know when you get \[\frac{1}{(x6)^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you have to use latex

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 7}\frac{\frac{x5}{x6}2}{x7}=\lim_{x \rightarrow 7}}\frac{x52(x6)}{(x6)(x7)\] =\[\lim_{x \rightarrow 7}\frac{x52x+12}{(x6)(x7)}=\lim_{x \rightarrow 7}\frac{x+7}{(x6)(x7)}=\lim_{x \rightarrow 7}\frac{(x7)}{(x6)(x7)}\] \[\lim_{x \rightarrow 7}\frac{1}{x6}=\frac{1}{76}=\frac{1}{1}=1\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no some of got messed up :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am totally impressed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the other hand i was trying to write a compound fraction because i was just trying to find the derivative, not the value at 7. good work!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow its gettin heated up in here

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i will rewrite the top

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myininaya is showing me up;(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahaha whose the better mathematician?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 7}\frac{\frac{x5}{x6}2}{x7}=\lim_{x \rightarrow 7}\frac{x6}{x6}\frac{\frac{x5}{x6}2}{x7}=\lim_{x \rightarrow 7}\frac{x52(x6)}{(x6)(x7)}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0satellite is way better than me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[lim_{h>0}\frac{\frac{x+h5}{x+h6}\frac{x5}{x6}}{h}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you like dem apples?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so anyways we found the slope of the tangent line to be 1 so a tangent line has form y=mx+b just like any other line we know m=1 we also know a point on the line (7,2) so we can find b 2=1(7)+b 2=7+b 2+7=b 9=b so the equation is y=x+9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right. once you have m = 1 it is all gravy from there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha sweet already worked it out. thanks guys
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