I have to find the vertex of: y= -3x^2+12x-8 and I have to plot it on a graph, providing an ordered pair as the vertex. I'm not understanding this at all. How should I begin?

- anonymous

- chestercat

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- Owlfred

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- anonymous

complete the sqaure

- anonymous

first factor out x^2 coeffiecnet

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## More answers

- anonymous

y = -3 ( x^2 -4x ) -8

- anonymous

note, we only factored out common factors on the x terms

- anonymous

then complete the sqaure in side the brackets

- anonymous

ok, it kinda makes sense so far..

- anonymous

to complete the square on x^2 -4x , we need to half the -4 ( to get -2 ) , the square it , and add and subtract inside the brackets

- anonymous

so y= -3 ( x^2 -4x + 4 - 4 ) - 8 // notice, its important you add and substract INSIDE THE BRACKET

- anonymous

we need to maintain equality

- anonymous

alright, with you on that

- anonymous

now you group the perfect sqaure inside the bracket

- anonymous

so y= -3 ( (x-2)^2 -4) -8

- anonymous

now you expand the brackets , being careful with the signs

- anonymous

so y= -3(x-2)^2 +12 -8

- anonymous

So I'm seeing here the only way the vertex can be solved is by doing the equation, then plotting it on the graph- how would I plot this #1, and #2, how would I come up with a solution set??

- anonymous

y= -3(x-2)^2 +4

- anonymous

vertex = (2,4)

- anonymous

you could do it other ways , you might the equation of axis of symmetry of a parabola is x=-b/2a

- anonymous

And how to plot? I have to do it on an online graph. Totally confused with it

- anonymous

and you know the vertex is on the axis of symmetry

- anonymous

I dont know there, I know how to do a general plot but have idea how the computer with mark you

- anonymous

"graph the equation by hand; find the vertex and round approximate coordinates to the second decimal place."

- anonymous

"Use the graphing tool to graph the parabola"

- anonymous

THIS is what is confusing me. Do I graph the solution set, I'm just not getting it. I understand for the most part the equation, but not plotting

- anonymous

One more equation- (x+8)^2+8(x+7)=64. I can solve by the method of my choice

- anonymous

Its not a negative sign in front of the x, I just need a solution set

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