anonymous
  • anonymous
I have to find the vertex of: y= -3x^2+12x-8 and I have to plot it on a graph, providing an ordered pair as the vertex. I'm not understanding this at all. How should I begin?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Owlfred
  • Owlfred
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anonymous
  • anonymous
complete the sqaure
anonymous
  • anonymous
first factor out x^2 coeffiecnet

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anonymous
  • anonymous
y = -3 ( x^2 -4x ) -8
anonymous
  • anonymous
note, we only factored out common factors on the x terms
anonymous
  • anonymous
then complete the sqaure in side the brackets
anonymous
  • anonymous
ok, it kinda makes sense so far..
anonymous
  • anonymous
to complete the square on x^2 -4x , we need to half the -4 ( to get -2 ) , the square it , and add and subtract inside the brackets
anonymous
  • anonymous
so y= -3 ( x^2 -4x + 4 - 4 ) - 8 // notice, its important you add and substract INSIDE THE BRACKET
anonymous
  • anonymous
we need to maintain equality
anonymous
  • anonymous
alright, with you on that
anonymous
  • anonymous
now you group the perfect sqaure inside the bracket
anonymous
  • anonymous
so y= -3 ( (x-2)^2 -4) -8
anonymous
  • anonymous
now you expand the brackets , being careful with the signs
anonymous
  • anonymous
so y= -3(x-2)^2 +12 -8
anonymous
  • anonymous
So I'm seeing here the only way the vertex can be solved is by doing the equation, then plotting it on the graph- how would I plot this #1, and #2, how would I come up with a solution set??
anonymous
  • anonymous
y= -3(x-2)^2 +4
anonymous
  • anonymous
vertex = (2,4)
anonymous
  • anonymous
you could do it other ways , you might the equation of axis of symmetry of a parabola is x=-b/2a
anonymous
  • anonymous
And how to plot? I have to do it on an online graph. Totally confused with it
anonymous
  • anonymous
and you know the vertex is on the axis of symmetry
anonymous
  • anonymous
I dont know there, I know how to do a general plot but have idea how the computer with mark you
anonymous
  • anonymous
"graph the equation by hand; find the vertex and round approximate coordinates to the second decimal place."
anonymous
  • anonymous
"Use the graphing tool to graph the parabola"
anonymous
  • anonymous
THIS is what is confusing me. Do I graph the solution set, I'm just not getting it. I understand for the most part the equation, but not plotting
anonymous
  • anonymous
One more equation- (x+8)^2+8(x+7)=64. I can solve by the method of my choice
anonymous
  • anonymous
Its not a negative sign in front of the x, I just need a solution set

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