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Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
complete the sqaure
first factor out x^2 coeffiecnet
y = -3 ( x^2 -4x ) -8
note, we only factored out common factors on the x terms
then complete the sqaure in side the brackets
ok, it kinda makes sense so far..
to complete the square on x^2 -4x , we need to half the -4 ( to get -2 ) , the square it , and add and subtract inside the brackets
so y= -3 ( x^2 -4x + 4 - 4 ) - 8 // notice, its important you add and substract INSIDE THE BRACKET
we need to maintain equality
alright, with you on that
now you group the perfect sqaure inside the bracket
so y= -3 ( (x-2)^2 -4) -8
now you expand the brackets , being careful with the signs
so y= -3(x-2)^2 +12 -8
So I'm seeing here the only way the vertex can be solved is by doing the equation, then plotting it on the graph- how would I plot this #1, and #2, how would I come up with a solution set??
y= -3(x-2)^2 +4
vertex = (2,4)
you could do it other ways , you might the equation of axis of symmetry of a parabola is x=-b/2a
And how to plot? I have to do it on an online graph. Totally confused with it
and you know the vertex is on the axis of symmetry
I dont know there, I know how to do a general plot but have idea how the computer with mark you
"graph the equation by hand; find the vertex and round approximate coordinates to the second decimal place."
"Use the graphing tool to graph the parabola"
THIS is what is confusing me. Do I graph the solution set, I'm just not getting it. I understand for the most part the equation, but not plotting
One more equation- (x+8)^2+8(x+7)=64. I can solve by the method of my choice
Its not a negative sign in front of the x, I just need a solution set