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anonymous
 5 years ago
I have to find the vertex of: y= 3x^2+12x8 and I have to plot it on a graph, providing an ordered pair as the vertex. I'm not understanding this at all. How should I begin?
anonymous
 5 years ago
I have to find the vertex of: y= 3x^2+12x8 and I have to plot it on a graph, providing an ordered pair as the vertex. I'm not understanding this at all. How should I begin?

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first factor out x^2 coeffiecnet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = 3 ( x^2 4x ) 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0note, we only factored out common factors on the x terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then complete the sqaure in side the brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, it kinda makes sense so far..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to complete the square on x^2 4x , we need to half the 4 ( to get 2 ) , the square it , and add and subtract inside the brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so y= 3 ( x^2 4x + 4  4 )  8 // notice, its important you add and substract INSIDE THE BRACKET

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we need to maintain equality

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, with you on that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you group the perfect sqaure inside the bracket

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so y= 3 ( (x2)^2 4) 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you expand the brackets , being careful with the signs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so y= 3(x2)^2 +12 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So I'm seeing here the only way the vertex can be solved is by doing the equation, then plotting it on the graph how would I plot this #1, and #2, how would I come up with a solution set??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you could do it other ways , you might the equation of axis of symmetry of a parabola is x=b/2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And how to plot? I have to do it on an online graph. Totally confused with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you know the vertex is on the axis of symmetry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont know there, I know how to do a general plot but have idea how the computer with mark you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"graph the equation by hand; find the vertex and round approximate coordinates to the second decimal place."

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"Use the graphing tool to graph the parabola"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THIS is what is confusing me. Do I graph the solution set, I'm just not getting it. I understand for the most part the equation, but not plotting

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One more equation (x+8)^2+8(x+7)=64. I can solve by the method of my choice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its not a negative sign in front of the x, I just need a solution set
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