anonymous
  • anonymous
From the graph of g, state the intervals on which g is continuous. Select all that apply. http://www.webassign.net/scalc/2-4-4.gif (-INFINITY, -4] (-INFINITY, -4) [-4,-2] [-4,-2) [-2,2] (-2,2) [2,4] [2,4) [4,6] (4,6) [6,8] (6,8) [8,INFINITY) (8,INFINITY)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
[-4,2)U(-2,2)U[2,4)U(4,6)U(6,8)
anonymous
  • anonymous
U SURE??
anonymous
  • anonymous
yeah..i'm pretty sure we learned this in calc.

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More answers

anonymous
  • anonymous
you cant include the end points,
anonymous
  • anonymous
in order to be continuous the function has to be defined at the point and have a limit at the point, and the two must equal each other.
anonymous
  • anonymous
x=-4, has not limit from the LHS, it cant be continuous, should be an open bracket
anonymous
  • anonymous
there is no open circle on 4
anonymous
  • anonymous
(-4,-2) , but they dont give that as an option
anonymous
  • anonymous
wat does it mean if there is no corcle at the end of something?
anonymous
  • anonymous
*circle
anonymous
  • anonymous
it means it includes that point
anonymous
  • anonymous
so wud that be open or closed?
anonymous
  • anonymous
but there is nothing to the left of it , there is no LHS limit
anonymous
  • anonymous
there is no way to approach x=-4 from the negative x axis , because its not defined , so strictly speaking it shouldnt be continuous there ( even though the answer doesnt give (-4,-2) as an interval that you can choose
anonymous
  • anonymous
sadas answrs were correct tho
anonymous
  • anonymous
yeh, but what was this ?, a online assignment site? , I am smarter than those computers
anonymous
  • anonymous
hahaha yeah it is
anonymous
  • anonymous
i just dont get waht it means when ther is no circle at the end of a line
anonymous
  • anonymous
eg when x=4
anonymous
  • anonymous
lol wud u know dumbcow?
anonymous
  • anonymous
when x=4, the function tends to infinity, therefore, there is no limit there, and if there is no limit, it cannot be continuous at that point.
anonymous
  • anonymous
but the answer was (4,6).....this implies that at 4 its open?
anonymous
  • anonymous
yes. it is open because it is not strictly defined at that point.
anonymous
  • anonymous
okay so it continues at that point right?
anonymous
  • anonymous
til infinity?
anonymous
  • anonymous
it is only continuous if it has a limit everywhere and if it is defined everywhere.. in the case of x=4, the limit tends to infinity (which means there is no real limit) so therefore, it cannot be continuous.
anonymous
  • anonymous
oh but the q asked for which interval is it continous?
anonymous
  • anonymous
yes, and that was elec's point.
anonymous
  • anonymous
lol im confused
anonymous
  • anonymous
The definition of continuity I was taught at uni was , has right hand side and left hand side limits equal and they must equal the function value
anonymous
  • anonymous
which point are you confused about and?
anonymous
  • anonymous
that if at x=4 is not continous how come the interval of (4,6) is continous
anonymous
  • anonymous
because we are using open brackets on both sides..with open brackets, you are not including the x=4 or the x=6 in your answer.
anonymous
  • anonymous
you need to learn your notation correctly
anonymous
  • anonymous
so basically at the end of 4 is an open bracket then
anonymous
  • anonymous
on the intervals [4,6) or (4,6] or [4,6] the function would be discontinuous
anonymous
  • anonymous
you just have to get use to interval notation
anonymous
  • anonymous
and..yes .. basically.
anonymous
  • anonymous
haha lol.ty sadas. which uni u go too elecengineer?
anonymous
  • anonymous
unsw
anonymous
  • anonymous
fair enuf. which high school did u go too?
anonymous
  • anonymous
south sydney high school , in maroubra, I live like 10minutes away from the uni
anonymous
  • anonymous
you porbably never heard of the school, its not really famous for anything , just an average school
anonymous
  • anonymous
cool.. i went to hurlstone agricultural high. ever heard of it b4 ?lol

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