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anonymous
 5 years ago
From the graph of g, state the intervals on which g is continuous. Select all that apply.
http://www.webassign.net/scalc/244.gif
(INFINITY, 4]
(INFINITY, 4)
[4,2]
[4,2)
[2,2]
(2,2)
[2,4]
[2,4)
[4,6]
(4,6)
[6,8]
(6,8)
[8,INFINITY)
(8,INFINITY)
anonymous
 5 years ago
From the graph of g, state the intervals on which g is continuous. Select all that apply. http://www.webassign.net/scalc/244.gif (INFINITY, 4] (INFINITY, 4) [4,2] [4,2) [2,2] (2,2) [2,4] [2,4) [4,6] (4,6) [6,8] (6,8) [8,INFINITY) (8,INFINITY)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[4,2)U(2,2)U[2,4)U(4,6)U(6,8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah..i'm pretty sure we learned this in calc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you cant include the end points,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in order to be continuous the function has to be defined at the point and have a limit at the point, and the two must equal each other.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=4, has not limit from the LHS, it cant be continuous, should be an open bracket

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no open circle on 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(4,2) , but they dont give that as an option

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wat does it mean if there is no corcle at the end of something?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it means it includes that point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so wud that be open or closed?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but there is nothing to the left of it , there is no LHS limit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no way to approach x=4 from the negative x axis , because its not defined , so strictly speaking it shouldnt be continuous there ( even though the answer doesnt give (4,2) as an interval that you can choose

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sadas answrs were correct tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh, but what was this ?, a online assignment site? , I am smarter than those computers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont get waht it means when ther is no circle at the end of a line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol wud u know dumbcow?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when x=4, the function tends to infinity, therefore, there is no limit there, and if there is no limit, it cannot be continuous at that point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the answer was (4,6).....this implies that at 4 its open?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes. it is open because it is not strictly defined at that point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so it continues at that point right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is only continuous if it has a limit everywhere and if it is defined everywhere.. in the case of x=4, the limit tends to infinity (which means there is no real limit) so therefore, it cannot be continuous.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh but the q asked for which interval is it continous?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, and that was elec's point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The definition of continuity I was taught at uni was , has right hand side and left hand side limits equal and they must equal the function value

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which point are you confused about and?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that if at x=4 is not continous how come the interval of (4,6) is continous

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because we are using open brackets on both sides..with open brackets, you are not including the x=4 or the x=6 in your answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to learn your notation correctly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so basically at the end of 4 is an open bracket then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the intervals [4,6) or (4,6] or [4,6] the function would be discontinuous

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just have to get use to interval notation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and..yes .. basically.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha lol.ty sadas. which uni u go too elecengineer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fair enuf. which high school did u go too?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0south sydney high school , in maroubra, I live like 10minutes away from the uni

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you porbably never heard of the school, its not really famous for anything , just an average school

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cool.. i went to hurlstone agricultural high. ever heard of it b4 ?lol
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