From the graph of g, state the intervals on which g is continuous. Select all that apply.
http://www.webassign.net/scalc/2-4-4.gif
(-INFINITY, -4]
(-INFINITY, -4)
[-4,-2]
[-4,-2)
[-2,2]
(-2,2)
[2,4]
[2,4)
[4,6]
(4,6)
[6,8]
(6,8)
[8,INFINITY)
(8,INFINITY)

- anonymous

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

[-4,2)U(-2,2)U[2,4)U(4,6)U(6,8)

- anonymous

U SURE??

- anonymous

yeah..i'm pretty sure we learned this in calc.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

you cant include the end points,

- anonymous

in order to be continuous the function has to be defined at the point and have a limit at the point, and the two must equal each other.

- anonymous

x=-4, has not limit from the LHS, it cant be continuous, should be an open bracket

- anonymous

there is no open circle on 4

- anonymous

(-4,-2) , but they dont give that as an option

- anonymous

wat does it mean if there is no corcle at the end of something?

- anonymous

*circle

- anonymous

it means it includes that point

- anonymous

so wud that be open or closed?

- anonymous

but there is nothing to the left of it , there is no LHS limit

- anonymous

there is no way to approach x=-4 from the negative x axis , because its not defined , so strictly speaking it shouldnt be continuous there ( even though the answer doesnt give (-4,-2) as an interval that you can choose

- anonymous

sadas answrs were correct tho

- anonymous

yeh, but what was this ?, a online assignment site? , I am smarter than those computers

- anonymous

hahaha yeah it is

- anonymous

i just dont get waht it means when ther is no circle at the end of a line

- anonymous

eg when x=4

- anonymous

lol wud u know dumbcow?

- anonymous

when x=4, the function tends to infinity, therefore, there is no limit there, and if there is no limit, it cannot be continuous at that point.

- anonymous

but the answer was (4,6).....this implies that at 4 its open?

- anonymous

yes. it is open because it is not strictly defined at that point.

- anonymous

okay so it continues at that point right?

- anonymous

til infinity?

- anonymous

it is only continuous if it has a limit everywhere and if it is defined everywhere.. in the case of x=4, the limit tends to infinity (which means there is no real limit) so therefore, it cannot be continuous.

- anonymous

oh but the q asked for which interval is it continous?

- anonymous

yes, and that was elec's point.

- anonymous

lol im confused

- anonymous

The definition of continuity I was taught at uni was , has right hand side and left hand side limits equal and they must equal the function value

- anonymous

which point are you confused about and?

- anonymous

that if at x=4 is not continous how come the interval of (4,6) is continous

- anonymous

because we are using open brackets on both sides..with open brackets, you are not including the x=4 or the x=6 in your answer.

- anonymous

you need to learn your notation correctly

- anonymous

so basically at the end of 4 is an open bracket then

- anonymous

on the intervals [4,6) or (4,6] or [4,6] the function would be discontinuous

- anonymous

you just have to get use to interval notation

- anonymous

and..yes .. basically.

- anonymous

haha lol.ty sadas.
which uni u go too elecengineer?

- anonymous

unsw

- anonymous

fair enuf. which high school did u go too?

- anonymous

south sydney high school , in maroubra, I live like 10minutes away from the uni

- anonymous

you porbably never heard of the school, its not really famous for anything , just an average school

- anonymous

cool.. i went to hurlstone agricultural high. ever heard of it b4 ?lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.