Given the function defined by t(x)=x^3-3x^2+2x-3 t(-1)

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Given the function defined by t(x)=x^3-3x^2+2x-3 t(-1)

Mathematics
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(-1)^3 - 3(-1)^2 + 2(1) -3 = -1-3+2-3 = -5
Oh i get it so you insert the -1 in every spot that x goes
Wouldn't it be -9 because you put a positive 1 with the 2 and it's actually negative

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\[(-1)^3-3(-1)^2+2(-1)-3= -1-3+-2-3=-9\]
Or did i understand it wrong? Correct me if i am?
Yes, you did it right. I'm sorry. I had made a mathematical error. the answer is -9
Yay! So you taught me something. Awesome!! Thanks. I APPRECIATE IT
Haha! No problem :)
Thanks for correcting me!
LOL. Well good night No problem i just actually want to learn not like other ppl that just get answers

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