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## anonymous 5 years ago how do you solve 4+5e^-x=0

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1. Owlfred

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

2. anonymous

Rearrange and take logarithm on both sides! :)

3. anonymous

i still don understand

4. anonymous

Subtracting 4 from both sides gives $$5e^{-x}=-4$$. Now divide both sides by 5, you get $$e^{-x}=- \frac{4}{5}$$. But the exponent function has only positive values in $$\ R$$. So, the equation has no real solutions.

5. anonymous

exponential function*

6. anonymous

u understood amberllg?

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