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anonymous

  • 5 years ago

how do you solve 4+5e^-x=0

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    Rearrange and take logarithm on both sides! :)

  3. anonymous
    • 5 years ago
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    i still don understand

  4. anonymous
    • 5 years ago
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    Subtracting 4 from both sides gives \(5e^{-x}=-4\). Now divide both sides by 5, you get \(e^{-x}=- \frac{4}{5}\). But the exponent function has only positive values in \( \ R \). So, the equation has no real solutions.

  5. anonymous
    • 5 years ago
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    exponential function*

  6. anonymous
    • 5 years ago
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    u understood amberllg?

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