anonymous
  • anonymous
Can someone explain how to solve \[3^{-1/3}\times27^{-1/2}\] Thanks! :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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mohsen
  • mohsen
\[3^{-1/3}\times3^{3(-1/2)}\] \[3^{-1/3+(-3/2)}\] \[3^{-1/3-3/2}\] \[3^{(-2-9)/6}\] \[3^{-11/6}\]
anonymous
  • anonymous
how do you simplify that further? :D
mohsen
  • mohsen
\[27=3^{3}\] then solve the fraction...

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mohsen
  • mohsen
\[a ^{m} \times a ^{n}=a ^{m+n}\] the base must equal...
anonymous
  • anonymous
i mean, how do you simplify \[3^{-11/6}\] further? because actually, i got that answer too. but the answer isn't in the choices given. thanks!
mohsen
  • mohsen
what the choices?
anonymous
  • anonymous
\[\sqrt[6]{3}\] \[\sqrt[6]{3}/9\] \[3\sqrt[6]{3}/2\] and \[3\sqrt[6]{3}\]
anonymous
  • anonymous
\[3^{-\frac{11}{6}} =3^{-2}.3^{1/6}={\sqrt[6]{3} \over 9}\]
mohsen
  • mohsen
the answer is \[\sqrt[6]{3}/9\] \[3^{-11/6}=\] \[\sqrt[6]{3^{-11}}\] \[\sqrt[6]{3^{1}/3^{12}}\] \[\sqrt[6]{3^{1}}/\sqrt[6]{12}\] \[\sqrt[6]{3}/3^{12(1/6)}\] \[\sqrt[6]{3}/3^{2}\] \[\sqrt[6]{3}/9\]
anonymous
  • anonymous
Anwara, how is 3−116=3−2.31/6 ?
mohsen
  • mohsen
wow,anwar.how do u do that?
anonymous
  • anonymous
i meant, how did you get to the 2nd equation? and thanks, mohsen!
anonymous
  • anonymous
Because \(-2+1/6= \frac{-12+1}{6}=-11/6\), which is the same exponent :)
anonymous
  • anonymous
@Mohsen: do what?
mohsen
  • mohsen
same question with phoebeca :) bt u answered it :) thanks
anonymous
  • anonymous
You're welcome!
anonymous
  • anonymous
thanks guys!
mohsen
  • mohsen
i'm a teacher but still impress your answer,anwar :)
anonymous
  • anonymous
i agree!
anonymous
  • anonymous
Thanks mohsen :)

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