A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
pls help me..
it is possible to project a particle from level ground with a given velocity in 2 possible ways so as to make it pass through a point on the ground at a distance r from the point of projection .The product of time taken to reach this point in the 2 possible ways is then proportional ro
a. r
b. 1/r
anonymous
 5 years ago
pls help me.. it is possible to project a particle from level ground with a given velocity in 2 possible ways so as to make it pass through a point on the ground at a distance r from the point of projection .The product of time taken to reach this point in the 2 possible ways is then proportional ro a. r b. 1/r

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is a) r. If the particle is thrown at an angle θ with initial velocity u, then r will be \[r = u ^{2}\sin2\theta/g ^{2}\] Then, the particle can be thrown with two different angles θ and (pi/2  θ) to pass through the same point at distance r. Now, the time taken for the particle is \[T1 = 2usin \theta/g\] and \[T2 = 2usin(\pi/2  \theta)/g = 2ucos \theta/g\] Now, (T1xT2) is proportional to r.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was stuck..thank u 4 helping... :) !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.