100 people are present in a party. If each of them must do a handshake with all the other people, how many handshakes should be done? Please explain how to get the answer, thanks!
Stacey Warren - Expert brainly.com
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you need 2 people for an hand shake and u have 100 people so i think that its C(100,2) but i am not sue of it..
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hmm i found the answer as 9900
if there are 3 people:
1,2 ; 1,3 ; 2,3 .... is that right?
Think about it like this: the first person has 99 people to shake hands with, the second person has 98 because they've already shaken hands with the first, the third has 97...
yea but its harder to calculate this like that... so i think C(100,2) better way of solve
5054 if we do that ..... add all the numbers from 1 to 100 :)
No, all the numbers from 1 to 99.
ack .... 99 then lol
wouldnt the last guy have noone to shake hands with?
mhmh yea but there is 100 people and they and we need 2 people to shake hands so that it should be 100 x 99 /2,
Yeah, the last guy has no-one to shake hands with, that's why it's sum of the first 99 integers, not the first 100.
yea you right
i get 5 people with 10 shakes 5(4)/2 = 10
8 people with 28 shakes 8(7)/2 = 28
I spose it works :)
100(99)/2 = 99*50 = 4950 yay!!