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anonymous
 5 years ago
How do I find the twelfth term of 5,8,11,14
anonymous
 5 years ago
How do I find the twelfth term of 5,8,11,14

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's an arithmetic progression. The formula for the nth term of an arithmetic progression is:\[u _{n}=a+(n1)d\]Where a is the first term and d is common difference. So, to find the twelfth term of this sequence:\[u _{12}=a+(121)d=5+11\times3=38\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's the recurrence relation but that's not particularly necessary here.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2i dont operate on necessary lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 3n + 2 :D( n = term) for n = 1(first term): 3 + 2 =5 for n= 2(second term): 6 + 2 = 8 for n=20(20th term) 60 + 2 = 62 kk?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just they way i solve is really easier

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2\(A_n = A_{n1}+3\); and \(A_{n1} = A_{n2}+3\) \[A_n = A_{n2}+3+3 \iff A_n=A_{n2}+2(3)\] \[A_n = A_{nr} + r(3)\] \(A_{nr} = A_1;\) when \(r = n1\) \[\] \(A_n = A_1 + (n1)(3);\) and \(A_1 = 5\) \[A_{12} = 5 + (121)(3) = 38\] Thats how you learn it in discrete math ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.097 to go and then i open a bottle of champagne!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.297..years? or seonds lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it happens when i am not here i will be sad

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2ill send a carrier pigeon just before it happens to let you know lol
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