## anonymous 5 years ago find the vertical asymptotes of the function givem (x^2+7)/(9x-5x^2) please provide the smallest value and the largest value of x.

1. anonymous

can you please show me step by step

2. anonymous

set the denominator = 0 and solve:

3. anonymous

$9x-5x^2=0$ $x(9-5x)=0$ $x=0$ or $x=\frac{9}{5}$

4. anonymous

5. anonymous

horizontal one is $y=-\frac{1}{5}$ since the degree of numerator and denominator are the same it is the ratio of the leading coefficients. not that you asked

6. anonymous

ok cool thank you veyr much

7. anonymous

welcome