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anonymous

  • 5 years ago

Identify the degree of each term of the polynomial and the degree of the polynomial. the degree of first term? degree of second? third? fourth? and the degree of the polynomial is?

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  1. anonymous
    • 5 years ago
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    -6x^3+6x^2+3x+5

  2. amistre64
    • 5 years ago
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    degree is just the highest exponent value of the term

  3. anonymous
    • 5 years ago
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    right.

  4. amistre64
    • 5 years ago
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    3,2,1,0;......3

  5. anonymous
    • 5 years ago
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    so can u breifly explain how you got at least one of the answers?

  6. amistre64
    • 5 years ago
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    i looked at the exponents to see what number it had, and determined that the number defines the degree of the term...

  7. anonymous
    • 5 years ago
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    the terms are : \[-6x^3\] \[6x^2\] \[3x\] \[5\]

  8. amistre64
    • 5 years ago
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    6x^2 has a 2 as an exponent, so its a degre of 2

  9. anonymous
    • 5 years ago
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    the degrees are the exponents, and the biggest one is 3

  10. amistre64
    • 5 years ago
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    its kinda like asking how tall you are, and then asking how you know your that tall. the tape measure says so :)

  11. anonymous
    • 5 years ago
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    oh so your looking at the x^3 x^2 x and then nothing , so the 3 is highest so that is first and then so on?

  12. amistre64
    • 5 years ago
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    yes

  13. anonymous
    • 5 years ago
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    5 counts as a term. its degree is 0

  14. anonymous
    • 5 years ago
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    so the degree os polynomial? how did u get that one

  15. amistre64
    • 5 years ago
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    poly degree is just highest degree of the terms

  16. amistre64
    • 5 years ago
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    x^3 is highest degreed term so poly degree is 3

  17. anonymous
    • 5 years ago
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    while we are at it there is more terminology. the LEADING COEFFICIENT is the coefficient of the term of highest degree so in this case it is -6

  18. anonymous
    • 5 years ago
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    ok gotcha woohoo thank you!!!!!!

  19. anonymous
    • 5 years ago
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    and the CONSTANT is the term of degree 0, so in this case it is 5

  20. anonymous
    • 5 years ago
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    thank you

  21. anonymous
    • 5 years ago
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    welcome

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