## A community for students. Sign up today

Here's the question you clicked on:

## anonymous 5 years ago solve x^2+6x-4=0

• This Question is Closed
1. anonymous

use the quadratic formula here

2. anonymous

here a=1, b=6, c= -4 x= [-b + sqrt(b^2 - 4 ac)]/2a

3. anonymous

just pkug in those numbers

4. anonymous

easier here to complete the square since the middle term is +x$x^2+6x=4$ $(x+3)^3=4+9=13$ $x+3=\pm\sqrt{13}$ $x=-3\pm\sqrt{13}$

5. anonymous

quadratic formula forces a denominator on you and then it is a pain to simplify

6. anonymous

x=[-6 + sqrt(6^2 -4(1)(-4))]/2(1) x=[ -6 + sqrt(36 + 16)]/2 x=[-6 + sqrt(52)]/2 x=[-6 + 2sqrt(13)]/2 x=[-3 + sqrt 13] and x= -3 - sqrt 13

7. anonymous

i think its also good for the beginers to learn to use the quadratic formula...lol

8. anonymous

it will be very much faster and fun to do it in calculator...lol

9. anonymous

i won't argue but i used 3 steps all dealing with whole numbers. of course the answers are the same, but writing is simplest radical form (correctly) and then factoring and canceling (correctly) is often a can of worms

10. anonymous

lol.....

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy