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anonymous

  • 5 years ago

solve x^2+6x-4=0

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  1. anonymous
    • 5 years ago
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    use the quadratic formula here

  2. anonymous
    • 5 years ago
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    here a=1, b=6, c= -4 x= [-b + sqrt(b^2 - 4 ac)]/2a

  3. anonymous
    • 5 years ago
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    just pkug in those numbers

  4. anonymous
    • 5 years ago
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    easier here to complete the square since the middle term is +x\[x^2+6x=4\] \[(x+3)^3=4+9=13\] \[x+3=\pm\sqrt{13}\] \[x=-3\pm\sqrt{13}\]

  5. anonymous
    • 5 years ago
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    quadratic formula forces a denominator on you and then it is a pain to simplify

  6. anonymous
    • 5 years ago
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    x=[-6 + sqrt(6^2 -4(1)(-4))]/2(1) x=[ -6 + sqrt(36 + 16)]/2 x=[-6 + sqrt(52)]/2 x=[-6 + 2sqrt(13)]/2 x=[-3 + sqrt 13] and x= -3 - sqrt 13

  7. anonymous
    • 5 years ago
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    i think its also good for the beginers to learn to use the quadratic formula...lol

  8. anonymous
    • 5 years ago
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    it will be very much faster and fun to do it in calculator...lol

  9. anonymous
    • 5 years ago
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    i won't argue but i used 3 steps all dealing with whole numbers. of course the answers are the same, but writing is simplest radical form (correctly) and then factoring and canceling (correctly) is often a can of worms

  10. anonymous
    • 5 years ago
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    lol.....

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