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anonymous
 5 years ago
find limt
lim x approaches infinity 1/(5x+4)
anonymous
 5 years ago
find limt lim x approaches infinity 1/(5x+4)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0denomiator gets bigger, numerator stays one. think of \[\frac{1}{1000000}=.000001\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bigger the denominator gets, the smaller the fraction.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so anything that deals with infinity could possibly be zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it depends on the function, but it certainly could be 0 in the limit.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. i have another one simliar but mor complex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ \lim \rightarrow \infty (1 xx^2)/(3x^24)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok in this case you have a polynomial of degree 2 in the numerator, and a polynomial of degree 2 in the denominator. when the degrees are the same, as in this case, just take the ratio of the leading coefficients.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0leading coefficient of the numerator is 1, and the leading coefficient of the denominator is 3 so the limit as x goes to infinity is 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what could be easier?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok..so basically you look into the coefficent of both numerator and denominator and computer it to become a 1/3...so the 4 in the denomintor and the numerator dont neccessary needs anything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not a thing. lets do a simple example: \[lim_{x>\infty}\frac{x^3+9x}{2x^2+x^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and lets let x = 100 which is not even that big

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the numerator is \[100^3+9\times 100=1000900\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the denominator is 2010000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the ratio is \[\frac{1000900}{2010000}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right and the denomator would be 2010000....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which is certainly not exactly \[\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you can see that it is close. you can also see that the 9x term and the x^2 term meant nothing as far as the magnitude of the numerator and denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are way down there in the decimal places.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need a lot of practice on this function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and that was just for 100. we are taking the limit as x > infinity. imagine what it would look like if x was 10000000000

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very very close to 1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is not how it is explained in your book. i am just pointing out that the numbers show you that you will get closer and closer to 1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see becuase you can basically pick any number in the infinity column and it would still be the coeffiencet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now if the degree of the denominator is bigger than the numerator, then the limit is 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0think of \[\frac{10^3}{10^5}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0numerator has degree 3, denom has degree 5 and this number is small. it is .01

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it would be zero because the 10^5 and large

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0last possibility is that the degree of the numerator is higher. in this case the limit is infinty

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now think of degree of the numerator bigger. for example \[\frac{10^5}{10^2}=1000\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and that is just for 10! as x > infinity this will get huge. so the rules are as follows (and very simple) lim x> infity p(x)/q(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if deg p > deg q, limit is infinity if deg p < deg q limit is 0 if deg p = deg q ratio of leading coefficients

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok no i see thanks again!!
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