A random sample of 1000 oranges showed that the mean amount of juice per orange was 7 fluid ounces, with a standard deviation of 1.6 fluid ounces. If the z-score for a particular orange was –1.5, how much juice was produced by this orange? Round approximate values to the nearest tenth of a fluid ounce.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

A random sample of 1000 oranges showed that the mean amount of juice per orange was 7 fluid ounces, with a standard deviation of 1.6 fluid ounces. If the z-score for a particular orange was –1.5, how much juice was produced by this orange? Round approximate values to the nearest tenth of a fluid ounce.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

7 -1.5 = 5.5
5.5\14 ?
7-1.5*1.6=4.6

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

well their is a 5.5 and 4.6
5.5 is its position
im looking for a calculator
The z score is standarised and tells you how many standard deviations away from the mean the orange is.
i really hate normal distribution
its not so normal
In a certain normal distribution of scores, the mean is 50 and the standard deviation is 4. Find the z-score corresponding to a score of 55.
Yes, it is normal. This orange is 1.5 standard deviations below the mean and the mean is 7 so the orange produces 7-1.5*1.6=4.6 fluid onces.
well im do this for the first time on the web... i should have done it in a class room with a real teacher
i get the 5.5 .... but whats the logic behind *zscore?
or is that 7-(1.5*1.6)
\[Z=\frac{X-\mu}{\sigma}\] so it tells you how many standard deviations below the mean a certain value is.
Yes, 7-(1.5*1.6)
stats class is a little confusing to me becasue the teacher is just throwing formulas at us with no explanation ...
50-(4*55)=
In a certain normal distribution of scores, the mean is 50 and the standard deviation is 4. Find the z-score corresponding to a score of 55.
did i do it right lol
No, see the formula I posed earlier. It should be (55-50)/4
what confuses me is the signs for the formula... but i got it
this is my first time ever doing this plez excuse me
Ah, ok, sorry. X is the number you're trying to find the Z value for, mu is the mean and sigma is the standard deviation.
but i understand it better than what the book would explain... its like 10 pages explain that formula
Remember, the z score just tells you how many standard deviations away from the mean a value is. So, say I had a mean of 50, and an SD of 2, if I was trying to find the z score of 56, it would be 3 because 56 is 3 standard deviations from the mean.

Not the answer you are looking for?

Search for more explanations.

Ask your own question