anonymous
  • anonymous
A random sample of 1000 oranges showed that the mean amount of juice per orange was 7 fluid ounces, with a standard deviation of 1.6 fluid ounces. If the z-score for a particular orange was –1.5, how much juice was produced by this orange? Round approximate values to the nearest tenth of a fluid ounce.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
7 -1.5 = 5.5
amistre64
  • amistre64
5.5\14 ?
anonymous
  • anonymous
7-1.5*1.6=4.6

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More answers

anonymous
  • anonymous
well their is a 5.5 and 4.6
amistre64
  • amistre64
5.5 is its position
anonymous
  • anonymous
im looking for a calculator
anonymous
  • anonymous
The z score is standarised and tells you how many standard deviations away from the mean the orange is.
anonymous
  • anonymous
i really hate normal distribution
anonymous
  • anonymous
its not so normal
anonymous
  • anonymous
In a certain normal distribution of scores, the mean is 50 and the standard deviation is 4. Find the z-score corresponding to a score of 55.
anonymous
  • anonymous
Yes, it is normal. This orange is 1.5 standard deviations below the mean and the mean is 7 so the orange produces 7-1.5*1.6=4.6 fluid onces.
anonymous
  • anonymous
well im do this for the first time on the web... i should have done it in a class room with a real teacher
amistre64
  • amistre64
i get the 5.5 .... but whats the logic behind *zscore?
amistre64
  • amistre64
or is that 7-(1.5*1.6)
anonymous
  • anonymous
\[Z=\frac{X-\mu}{\sigma}\] so it tells you how many standard deviations below the mean a certain value is.
anonymous
  • anonymous
Yes, 7-(1.5*1.6)
amistre64
  • amistre64
stats class is a little confusing to me becasue the teacher is just throwing formulas at us with no explanation ...
anonymous
  • anonymous
50-(4*55)=
anonymous
  • anonymous
In a certain normal distribution of scores, the mean is 50 and the standard deviation is 4. Find the z-score corresponding to a score of 55.
anonymous
  • anonymous
did i do it right lol
anonymous
  • anonymous
No, see the formula I posed earlier. It should be (55-50)/4
anonymous
  • anonymous
what confuses me is the signs for the formula... but i got it
anonymous
  • anonymous
this is my first time ever doing this plez excuse me
anonymous
  • anonymous
Ah, ok, sorry. X is the number you're trying to find the Z value for, mu is the mean and sigma is the standard deviation.
anonymous
  • anonymous
but i understand it better than what the book would explain... its like 10 pages explain that formula
anonymous
  • anonymous
Remember, the z score just tells you how many standard deviations away from the mean a value is. So, say I had a mean of 50, and an SD of 2, if I was trying to find the z score of 56, it would be 3 because 56 is 3 standard deviations from the mean.

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