## anonymous 5 years ago (w-6/w-8)-(w+1/w+8)+(w-40/w^2-64)=?????????

1. mathteacher1729

Are you being asked to simplify the following? $\frac{w-6}{w-8}+\frac{w+1}{w+8}+\frac{w-40}{w^2-64}$

2. anonymous

yes

3. anonymous

no

4. anonymous

the 1 st is minus

5. anonymous

(w-6/w-8)-(w+1/w+8)+(w-40/w^2-64)

6. mathteacher1729

$\frac{w-6}{w-8}-\frac{w+1}{w+8}+\frac{w-40}{w^2-64}$

7. mathteacher1729

Since you're being asked to simplify, you want all three fractions to have a common denominator. Luckily $w^2-64 =(w+8)(w-8)$ so that means we can leave that term alone and multiply the others like this: $\frac{w-6}{w-8}\cdot\frac{w+8}{w+8}-\frac{w+1}{w+8}\cdot\frac{w-8}{w-8}+\frac{w-40}{w^2-64}$ That LOOKS like a gigantic mess... But it gets better. We now have a common denominator... $\frac{(w-6)(w-8) - (w+1)(w-8) + (w-40)}{w^2-64}$ And THAT just requires us to distribute and collect terms. :) Hope this helps!