Determine an equation of the line of intersection of the planes 5x+y+2z+15=0 and 2x+y+2z+8=0. Answers is equation = (-7,20,0)+t(0,-2,1)

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Determine an equation of the line of intersection of the planes 5x+y+2z+15=0 and 2x+y+2z+8=0. Answers is equation = (-7,20,0)+t(0,-2,1)

Mathematics
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I know how to find the direction vector (0,-2,1) but what about the point?
5x+y+2z+15 = 2x+y+2z+8 5x +y +2z +15 -2x -y -2z -8 ----------------- 3x + 7 = 0
x = -7/3 seems to be the line of intersection if i did it right

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i dont think I did it right :)
oh lol
yeah i figured it out
First we find the direction vector by crossing the normals of each line
sounds good
then we can find a point that is on both lines by finding a point that satisfies both equation
im sure you probably knew all this :P
medal still for you pops :D
its rattling around up there someplace inbetween the rafters lol
lol .. highschool ?
nah..... high school went and gone many many years ago
lol .. PhD?
:P

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