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anonymous

  • 5 years ago

Determine an equation of the line of intersection of the planes 5x+y+2z+15=0 and 2x+y+2z+8=0. Answers is equation = (-7,20,0)+t(0,-2,1)

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  1. anonymous
    • 5 years ago
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    I know how to find the direction vector (0,-2,1) but what about the point?

  2. amistre64
    • 5 years ago
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    5x+y+2z+15 = 2x+y+2z+8 5x +y +2z +15 -2x -y -2z -8 ----------------- 3x + 7 = 0

  3. amistre64
    • 5 years ago
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    x = -7/3 seems to be the line of intersection if i did it right

  4. amistre64
    • 5 years ago
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    i dont think I did it right :)

  5. anonymous
    • 5 years ago
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    oh lol

  6. anonymous
    • 5 years ago
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    yeah i figured it out

  7. anonymous
    • 5 years ago
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    First we find the direction vector by crossing the normals of each line

  8. amistre64
    • 5 years ago
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    sounds good

  9. anonymous
    • 5 years ago
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    then we can find a point that is on both lines by finding a point that satisfies both equation

  10. anonymous
    • 5 years ago
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    im sure you probably knew all this :P

  11. anonymous
    • 5 years ago
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    medal still for you pops :D

  12. amistre64
    • 5 years ago
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    its rattling around up there someplace inbetween the rafters lol

  13. anonymous
    • 5 years ago
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    lol .. highschool ?

  14. amistre64
    • 5 years ago
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    nah..... high school went and gone many many years ago

  15. anonymous
    • 5 years ago
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    lol .. PhD?

  16. anonymous
    • 5 years ago
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    :P

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