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anonymous

  • 5 years ago

((2+i)/(3-i))+((2-i)/(4i)) explanation please

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  1. anonymous
    • 5 years ago
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    do u know that these are complex numbers eg 2 + i

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    u need to rationalise the denominators by multiplying them by their complements the complement of 3-i is 3+i (changed sign) so we have (2+i)((3+i)/(3-i)(3+i) + (2-i)4i / 4i(4i) (6+2i+3i -1)/ 9+1 + 8i +4/-16 (5 +5i )/ 10 - (8i+4)16

  4. anonymous
    • 5 years ago
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    what do i do after that?

  5. anonymous
    • 5 years ago
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    i suppose we should write it as one fraction (1+i) / 2 - (2i+1) / 4 = (2+2i )/ 4 - (2i+1) / 4 = 1/4

  6. anonymous
    • 5 years ago
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    do i need a common denominator?

  7. anonymous
    • 5 years ago
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    wow - that neat- if i'm right of couse

  8. anonymous
    • 5 years ago
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    you are i checked it on my calculator but i didnt know how to get it.... and i factor right?

  9. anonymous
    • 5 years ago
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    sorry i dont know exactly what you mean (i'm a brit see!!)

  10. anonymous
    • 5 years ago
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    nevermind but thanks

  11. anonymous
    • 5 years ago
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    i understand it now

  12. anonymous
    • 5 years ago
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    good

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spraguer (Moderator)
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