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anonymous
 5 years ago
Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the lawn together?
anonymous
 5 years ago
Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the lawn together?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let x = the time for both to mow the same lawn working together.\[\frac{1}{6}+\frac{1}{4}\text{=}\frac{1}{x} \]\[\frac{5}{12}\text{= }\frac{1}{x}\]Solve for x. The dimensional unit for x is hours. Another view. \[\frac{1}{6}+\frac{1}{4}=\frac{5}{12} \]Jack and Marilyn can mow 5 lawns in 12 hours. You divide the numerator and denominator by 5 to determine how long it would take to Jack an Marilyn to move the equivalent of one lawn in hours.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0error in the last sentence. The word move should be replaced with the word mow.
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