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anonymous

  • 5 years ago

show me how to solve this equation please: c^2+(3c)+2=0

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. mathteacher1729
    • 5 years ago
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    This is a quadratic equation. It can be factored into two binomials. In pictures, you want to find values of x where the curve intersects the x axis. (see picture)

  3. anonymous
    • 5 years ago
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    Factorise (split into brackets):\[c^2+3c+2=(c+2)(c+1)=0\]Then, you have two numbers that when multiplied together make 0, so one of them is zero. So, either:\[c+2=0=>c=-2\]or\[c+1=0=>c=-1\]

  4. mathteacher1729
    • 5 years ago
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    To avoid confusion with equal/greater than signs: \Rightarrow \[\Rightarrow\]

  5. anonymous
    • 5 years ago
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    Ah, thanks! I wondered if there was a proper implies sign on her.

  6. mathteacher1729
    • 5 years ago
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    Draw your desired symbol, it gives you the code: http://detexify.kirelabs.org/classify.html Truly, we live in the future!

  7. anonymous
    • 5 years ago
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    Wow!

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