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anonymous

  • 5 years ago

Determine the point of intersection between the lines (x-3,y-20,z-7)=t(2,-4,5) ter, and (x-5)/2 = y-2 = (z+4)/-3 - AMISTRE64 HELP PLEASE!

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  1. anonymous
    • 5 years ago
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    answer is no intersection / skew lines but how?!

  2. anonymous
    • 5 years ago
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    yay amistre :D !

  3. amistre64
    • 5 years ago
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    since they are in 3d space; they can look to cross, but actually never touch. such as the line in the ceiling and the line on the floor both make it to a corner but never intersect each other

  4. anonymous
    • 5 years ago
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    how do you prove that mathematically. i do understand that concept that you just mentioned

  5. anonymous
    • 5 years ago
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    i can get the second equation in terms of x y and z but how do i sub that in to the second equation and how do i deal with t(2,-4,5) ? !

  6. anonymous
    • 5 years ago
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    that is how far i have went ... just stuck at that step

  7. amistre64
    • 5 years ago
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    we prove it by seeing if the scalar for one line vector equates to the scalar in the other ... but i gotta review it real quick to recall some details

  8. anonymous
    • 5 years ago
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    kay take your time boss :)

  9. amistre64
    • 5 years ago
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    when lines intersect... (x-3,y-20,z-7) = t(2,-4,5) ter ?ter? whats this?

  10. anonymous
    • 5 years ago
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    its one of the two equationse that intersect .. the format of this eqaution has confused memyself

  11. amistre64
    • 5 years ago
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    whats the ?ter? mean i take it its a typo of some kind

  12. anonymous
    • 5 years ago
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    ter means where value of t can me any real number sorry .. u knw like xer

  13. amistre64
    • 5 years ago
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    (x-5)/2 = y-2 = (z+4)/-3 a=2; b=1 ; c=-3 ; just the denoms of your things here right?

  14. amistre64
    • 5 years ago
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    t<2,1,-3> is the vector and P(5,2,-4)

  15. anonymous
    • 5 years ago
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    yeah denoms are right

  16. amistre64
    • 5 years ago
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    x = 5 +2t y = 2 + t z = -3 -4t for our equation of a line in R^3 or at least one of them

  17. anonymous
    • 5 years ago
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    you mean z = -4-3t ?

  18. amistre64
    • 5 years ago
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    (x-3,y-20,z-7)=t(2,-4,5) x= 3 +2t y= 20 -4t z= 7 +5t is our other line right?

  19. amistre64
    • 5 years ago
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    yeah :) lol

  20. anonymous
    • 5 years ago
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    hmm but how did you get that parametric equation ... you just diregarded x- y- etc?

  21. amistre64
    • 5 years ago
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    now we equate our x=x but use a different variable to indicate our scalar; say s instead of t and solve for the system of equations

  22. amistre64
    • 5 years ago
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    x-3 means x = 3 + vector x component

  23. amistre64
    • 5 years ago
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    x-x0 = Vx x = x0 + Vx

  24. anonymous
    • 5 years ago
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    oh true indeed

  25. amistre64
    • 5 years ago
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    5 +2t = 3 +2s 2 + t = 20 -4s -4 -3t = 7+5s

  26. amistre64
    • 5 years ago
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    solve for s and t and see if they match in the 3rd spot

  27. anonymous
    • 5 years ago
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    hmm :O i can work the rest you can help other people as with with great power comes great responsibilities :P

  28. amistre64
    • 5 years ago
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    if i start sticking to the walls ........

  29. amistre64
    • 5 years ago
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    it prolly means i need a bath lol

  30. anonymous
    • 5 years ago
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    lmfao xD

  31. amistre64
    • 5 years ago
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    if the system of equations creates s and t to meet at a common point; then they intersect there; if not then they never meet

  32. anonymous
    • 5 years ago
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    GOT IT YAY :) ! Love you man .. studying to get int queens university bro :(

  33. anonymous
    • 5 years ago
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    i got it just got to maintain their conditional offer :)

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