anonymous
  • anonymous
anyone...Pls help A commuter travels to work, driving a distance d at speed r. At the end of the day, she returns home and drives the same distance 4 mph faster, at a speed r+4. Her average speed for the round trip can be represented by the expression 2d/(d/r)+(d/r+4)
Mathematics
schrodinger
  • schrodinger
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dumbcow
  • dumbcow
avg speed = total distance/total time d = r*t => t=d/r total distance = 2d total time = d/r + d/r+4 = (d(r+4) + dr)/r(r+4) = (2dr+4d)/r(r+4) avg speed = 2d*(r(r+4)/2d(r+2) = r(r+4)/(r+2) wait what are we trying to solve for...
anonymous
  • anonymous
it also says simplify this expression and then gives me 4 choices as follows
anonymous
  • anonymous
r(r+4)/(r+2) or r(r+2)/(r+4) or dr(r+4)/(dr+2) or 1/ (r+2)

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dumbcow
  • dumbcow
ok then look at what i did above A)
anonymous
  • anonymous
yep...thanks you r awesome

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