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anonymous

  • 5 years ago

Factor completely 9x^6-54x^5+18x^4 the complete factorization is????

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  1. amistre64
    • 5 years ago
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    take out commons; x^4 seems the most commmon

  2. amistre64
    • 5 years ago
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    9 also goes into it all

  3. amistre64
    • 5 years ago
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    9x^4 (x^2 -6x +2)

  4. amistre64
    • 5 years ago
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    the rest might me tricky in that i think we get sqrts involved

  5. amistre64
    • 5 years ago
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    3 +- sqrt(28)/2 ad that aint gona be pretty

  6. amistre64
    • 5 years ago
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    3 +- sqrt(7) its either what I first did or it will ome to this: 9x^4(x -(3-sqrt(7)))(x-(3+sqrt(7))) if I kept track of it

  7. anonymous
    • 5 years ago
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    9x^4 (x^2 -6x +2) this is your first answer right?

  8. anonymous
    • 5 years ago
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    you have a few things going on so wasnt sure if that was the answer

  9. anonymous
    • 5 years ago
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    You are correct (except you left out x=0 as one of the solutions. the remaining x^2-6x+2 factors out to 3 + sqrt(7) and 3-sqrt(7) Use the pythagorean theorem to get the above answers. ax^2+bx+c=0 so a=1, b=-6, and c = 2; just plug those into the theorem to get 3 + sqrt(7) and 3-sqrt(7)

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