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anonymous
 5 years ago
x^32x^2+5x4=0
solve for x
anonymous
 5 years ago
x^32x^2+5x4=0 solve for x

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1+ 1,2,4 x=2? 2  1 2 5 4 0 2 0 10  1 0 5 6 nope, but since its all+ it aint bigger than 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait how'd you get 2 and 4?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x=1? 1  1 2 5 4 0 1 1 4  1 1 4 0 goody (x+1)(x^2 x +4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the rule is: factors of last#  factors of first#

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1typo (x1)(x^2 x +4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11,2,4  leads to our options to test 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14 factors to what? 1.4 ; 2.2 all the factors of 4 are: 1,2,4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what is our last number in the equation?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the last number is always a product of 2 other numbers ....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11(4) = 4 2(2) = 4 thats all we get right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i dont understand that..... im only in algebra 2..... all i know is you graph it and you get x=1, then i don't know what to do from there

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1well, if x=1; then that means that (x1) is a factor and you divide it out of the original equation to get whats left

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i get a remainder and i dont know what to do with it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you dont get a remainder ....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when i synthetically divide i got 2 as a remainder

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooooo. i see i forgot the negative sign okay so i got a remainder of 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then i get (x1)(x^2x+4) now what

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^2 x +4  x1  x^3 2x^2 +5x 4 +x^2  x^2 +5x  x  4x 4 +4  0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then do i use the quadratic formula?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you can try; but your gonna end up with a sqrt() whih means it wont factor over the reals

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know what that is..... but do i get an imaganary number?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you get imaginary numbers yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay... can you help me with this? ((2)/(x+2))((x)/(2x))=((x^2+4)/(x^24))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12 x x^2+4    =  x+2 2x x^24 ^^^ (x2) 2 x x^2+4    =  2x 2x x^24 2(2x) x(2x) x^2+4    =  4 x^2 x^24

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea and then i got 4/(x+2) but i dont know how to solve for x from there

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14 +2x 2x +x^2 x^2+4  =  (x^24) x^24 4x^2 = x^2+4 x^2 = x^2 when x=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that almost works :) but 1 doesnt= 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold on let me check my work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait what would the answer be then?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1let me do it on paper to keep better track of it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait how'd you get (x^24) in the denom. i only got (x^24)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when i simplify i get 4/(x+2) but i dont know what to do from there

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12(2x) x(2+x) = x^2 +4 4 2x 2x x^2 = x^2+4 0 = x^2+x^2 +4x +44 0 = 2x^2 +4x 0 = 2x(x+2) x = 0, 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get rid of the denom.?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i multiplied evething by x^24; but i got an error still

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok well can you just tell me how to solve 4/(x+2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1there is no solution; you end up with 0=8

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2}{x+2}\frac{x}{2x}=\frac{x^2 +4}{(x2)(x+2)}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2(x+2)(x2)}{x+2} + \frac{x(x+2)(x2)}{x+2}=x^2+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0shouldnt the right hand side have a denom.?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no denom, it canceled: \[frac{(x^2+4)(x2)(x+2)}{(x2)(x+2)}\] cancels \[2(x2)+x(x2)=x^2+4\] \[2x4+x^22x=x^2+4\] \[x^2 4 = x^2+4\] \[x^2x^2 = 4+4\] \[0=8 \implies \emptyset \]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{(x^2+4)(x−2)(x+2)}{(x−2)(x+2)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i dont see how it cancels on the left hand side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omygosh thank you soooo much :)
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