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anonymous

  • 5 years ago

Water must be mixed with a 15% hydrochloric acid solution to dilute the concentration to 5%. How many liters of water should be added if we need 19 liters of the 5% solution? Round to the nearest tenth. Answer is 12.7 liters..cannot figure out equation to get 12.7 liters...keep coming up with 6.33333..ect. Cannot figure out how to check problem, with answer.

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. amistre64
    • 5 years ago
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    h+w = 19 ; h = 19-w h(.15) +w(1) = 19(.05) .......................................... (19-w)(.15) +w(1) = 19(.05) 2.85 -.15w +w = 0.95 .85w = -1.9 w = -2.235..now where did i go wrong lol

  3. amistre64
    • 5 years ago
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    is water 0 instead of 1?

  4. dumbcow
    • 5 years ago
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    yes water is 0% concentration

  5. amistre64
    • 5 years ago
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    (19-w)(.15) +w(0) = 19(.05) 2.85 -.15w = 0.95 -.15w = -1.9 w = 12.666......

  6. amistre64
    • 5 years ago
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    we got hard water here kol

  7. anonymous
    • 5 years ago
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    Your answer is very close, amistre64...

  8. anonymous
    • 5 years ago
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    if we rounded it, it would get me 12.7liters..

  9. dumbcow
    • 5 years ago
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    they prob rounded the answer

  10. amistre64
    • 5 years ago
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    w*1 lol .....

  11. anonymous
    • 5 years ago
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    Could either of you also explain how to check this problem with the answer?

  12. amistre64
    • 5 years ago
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    well, by substituting it back into the original equation to see if it works out

  13. amistre64
    • 5 years ago
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    amount(%) + amount(%) = total amount(%)

  14. dumbcow
    • 5 years ago
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    (12.7)(.05) = (6.3)(.15) +0

  15. dumbcow
    • 5 years ago
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    oops (19)(.05) = (6.3)(.15)

  16. anonymous
    • 5 years ago
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    I'll try amestre's equation now...if I don't come up with amestre's answer...I'll be coming back to this site definitely..maybe within the hour. :)

  17. anonymous
    • 5 years ago
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    amistre64, could you explain why you set up your equation the way you did, in relation to the problem? How does (19-w)(.15)+w(0) relate to the problem? Sorry for asking such dumb questions...but it's late and I relate to words better than just numbers..

  18. amistre64
    • 5 years ago
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    well.... we know that we want a mix of hydroacid and water that equals 19 liters; that restricts us to: h+w = 19. It is easier to solve an equation when everything is in one variable; so since we want the amount of water, lets get h in terms of w h = 19 liters - water amount (h=19-w)

  19. amistre64
    • 5 years ago
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    h(15%) is the strength of the hydroacid (19-w)(.15) is stateing the same thing but using terms in water...

  20. amistre64
    • 5 years ago
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    the rest should be self explanatory id assume

  21. anonymous
    • 5 years ago
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    I'll look at the equation again,see if I can get my lightbulb on...

  22. amistre64
    • 5 years ago
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    :) good luck

  23. anonymous
    • 5 years ago
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    At any rate, I've saved your formula in a document amistre64, in case I can't figure it out tonight...:)

  24. amistre64
    • 5 years ago
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    itll make more sense after a 4course meal :)

  25. anonymous
    • 5 years ago
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    I don't think I've ever had one of those...:P

  26. anonymous
    • 5 years ago
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    The light-bulb is starting to spark...but it's not on quite yet..

  27. anonymous
    • 5 years ago
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    Okay, listening to some of Bach's music has helped turn the light-bulb on...and now I'm wondering how it can be this simple...:P

  28. anonymous
    • 5 years ago
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    Thanks for your help, guys...I'll definitely be using this site more often from now on, with me majoring in nursing at the moment. :)

  29. amistre64
    • 5 years ago
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    youre welcome :)

  30. anonymous
    • 5 years ago
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    Hold on, where did you get the 2.85 in your equation, amistre64?

  31. anonymous
    • 5 years ago
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    dumbcow, do you know where amistre64's 2.85 came from, in his equation?

  32. anonymous
    • 5 years ago
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    Could somebody explain this equation step by step, all the way through to the end? Don't assume something is self-explanatory...it's never like that with me.

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