anonymous
  • anonymous
Water must be mixed with a 15% hydrochloric acid solution to dilute the concentration to 5%. How many liters of water should be added if we need 19 liters of the 5% solution? Round to the nearest tenth. Answer is 12.7 liters..cannot figure out equation to get 12.7 liters...keep coming up with 6.33333..ect. Cannot figure out how to check problem, with answer.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Owlfred
  • Owlfred
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amistre64
  • amistre64
h+w = 19 ; h = 19-w h(.15) +w(1) = 19(.05) .......................................... (19-w)(.15) +w(1) = 19(.05) 2.85 -.15w +w = 0.95 .85w = -1.9 w = -2.235..now where did i go wrong lol
amistre64
  • amistre64
is water 0 instead of 1?

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dumbcow
  • dumbcow
yes water is 0% concentration
amistre64
  • amistre64
(19-w)(.15) +w(0) = 19(.05) 2.85 -.15w = 0.95 -.15w = -1.9 w = 12.666......
amistre64
  • amistre64
we got hard water here kol
anonymous
  • anonymous
Your answer is very close, amistre64...
anonymous
  • anonymous
if we rounded it, it would get me 12.7liters..
dumbcow
  • dumbcow
they prob rounded the answer
amistre64
  • amistre64
w*1 lol .....
anonymous
  • anonymous
Could either of you also explain how to check this problem with the answer?
amistre64
  • amistre64
well, by substituting it back into the original equation to see if it works out
amistre64
  • amistre64
amount(%) + amount(%) = total amount(%)
dumbcow
  • dumbcow
(12.7)(.05) = (6.3)(.15) +0
dumbcow
  • dumbcow
oops (19)(.05) = (6.3)(.15)
anonymous
  • anonymous
I'll try amestre's equation now...if I don't come up with amestre's answer...I'll be coming back to this site definitely..maybe within the hour. :)
anonymous
  • anonymous
amistre64, could you explain why you set up your equation the way you did, in relation to the problem? How does (19-w)(.15)+w(0) relate to the problem? Sorry for asking such dumb questions...but it's late and I relate to words better than just numbers..
amistre64
  • amistre64
well.... we know that we want a mix of hydroacid and water that equals 19 liters; that restricts us to: h+w = 19. It is easier to solve an equation when everything is in one variable; so since we want the amount of water, lets get h in terms of w h = 19 liters - water amount (h=19-w)
amistre64
  • amistre64
h(15%) is the strength of the hydroacid (19-w)(.15) is stateing the same thing but using terms in water...
amistre64
  • amistre64
the rest should be self explanatory id assume
anonymous
  • anonymous
I'll look at the equation again,see if I can get my lightbulb on...
amistre64
  • amistre64
:) good luck
anonymous
  • anonymous
At any rate, I've saved your formula in a document amistre64, in case I can't figure it out tonight...:)
amistre64
  • amistre64
itll make more sense after a 4course meal :)
anonymous
  • anonymous
I don't think I've ever had one of those...:P
anonymous
  • anonymous
The light-bulb is starting to spark...but it's not on quite yet..
anonymous
  • anonymous
Okay, listening to some of Bach's music has helped turn the light-bulb on...and now I'm wondering how it can be this simple...:P
anonymous
  • anonymous
Thanks for your help, guys...I'll definitely be using this site more often from now on, with me majoring in nursing at the moment. :)
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
Hold on, where did you get the 2.85 in your equation, amistre64?
anonymous
  • anonymous
dumbcow, do you know where amistre64's 2.85 came from, in his equation?
anonymous
  • anonymous
Could somebody explain this equation step by step, all the way through to the end? Don't assume something is self-explanatory...it's never like that with me.

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