anonymous
  • anonymous
The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle. please show all work!
Mathematics
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anonymous
  • anonymous
The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle. please show all work!
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
the angles are x, 3x, (x+3x+10)=4x+10. The sum must be 180 x+3x+4x+10=180 8x=170 x=85/4 The third angle was 4x+10 4(85/4)+10=95
anonymous
  • anonymous
Let the three angles be <1, <2, <3. We know that the sum of angles of a triangle should be 180. So eqn.1 is <1 + <2 + <3 = 180 -----(1) <2=3*<1----(2) <3=10+<1+<2 ------(3) Now solve the equations (1),(2),(3)

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