anonymous
  • anonymous
5/4x+1/8x=5/8+x ?? I am so bad at fractions
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
like this?: \[\frac{5}{4}x+\frac{1}{8}x=\frac{5}{8}+x\]
anonymous
  • anonymous
yes but how do you solve it??
anonymous
  • anonymous
ok, multiply everything by 8: 10x+x=5+8x 3x=5 x=5/3

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok
anonymous
  • anonymous
why do we multiply itby 8 b/c it is the common denominator?
anonymous
  • anonymous
its the least common multiple of the denominators, so it gets rid of all the fractions.
anonymous
  • anonymous
ok I will kepp that in mind thank you..
anonymous
  • anonymous
you're welcome
anonymous
  • anonymous
do you k now anything about the elimination method?
anonymous
  • anonymous
do you have a specific problem?
anonymous
  • anonymous
just getting it to opposite and yes! the 5x+6y=2 10x+12y=4
anonymous
  • anonymous
well those equations are multiples of each other
anonymous
  • anonymous
so elimination isnt really useful here
anonymous
  • anonymous
that answer calls for use of the elimination
anonymous
  • anonymous
to eliminate either x or y you multiply the first equation by -2, then add. But then you get 0=0
anonymous
  • anonymous
there are actually many solutions to that system
anonymous
  • anonymous
theyre both the same equation
anonymous
  • anonymous
there is an option for no solutions or many solutions
anonymous
  • anonymous
so many solutions woiuld fit
anonymous
  • anonymous
there are many solutions, because theyre both the same equation so you can pick any x and find a corresponding y to make the equation true
anonymous
  • anonymous
thank you again
anonymous
  • anonymous
but something like 2x+3y=15 4x+y=20 you would multiply the first equation by -2 and then add them together to eliminate x -4x-6y=-30 4x+y=20 -5y=-10 y=2 then plug back in to find x 2x+6=15 x=9/2
anonymous
  • anonymous
then the solution is unique

Looking for something else?

Not the answer you are looking for? Search for more explanations.