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anonymous
 5 years ago
5/4x+1/8x=5/8+x ?? I am so bad at fractions
anonymous
 5 years ago
5/4x+1/8x=5/8+x ?? I am so bad at fractions

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like this?: \[\frac{5}{4}x+\frac{1}{8}x=\frac{5}{8}+x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes but how do you solve it??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, multiply everything by 8: 10x+x=5+8x 3x=5 x=5/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why do we multiply itby 8 b/c it is the common denominator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its the least common multiple of the denominators, so it gets rid of all the fractions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I will kepp that in mind thank you..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you k now anything about the elimination method?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you have a specific problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just getting it to opposite and yes! the 5x+6y=2 10x+12y=4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well those equations are multiples of each other

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so elimination isnt really useful here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that answer calls for use of the elimination

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to eliminate either x or y you multiply the first equation by 2, then add. But then you get 0=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are actually many solutions to that system

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theyre both the same equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is an option for no solutions or many solutions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so many solutions woiuld fit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are many solutions, because theyre both the same equation so you can pick any x and find a corresponding y to make the equation true

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but something like 2x+3y=15 4x+y=20 you would multiply the first equation by 2 and then add them together to eliminate x 4x6y=30 4x+y=20 5y=10 y=2 then plug back in to find x 2x+6=15 x=9/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then the solution is unique
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