## anonymous 5 years ago x-sqrt{x+3}=x/2

Rewrite the equation as $$x-(x/2)=\sqrt{x+3}$$ $$x/2=\sqrt{x+3}$$ Square both sides $$x^2/4=x+3$$ $$x^2=4x+12$$ $$x^2-4x-12=0$$ $$(x-6)(x+2)=0$$ $$x=6$$ or $$x=-2$$ After inspection $$x=-2$$ doesn't work. So $$x=6$$ is the only solution!