anonymous
  • anonymous
help please in 1920 the record for a certain race was 45.9 seconds. In 1960 it was 44.7 sec. let R(t) = the record in the race and t=the number of years since 1920. a. find a linear function that fits the data b. use the function in (a) to predict the record in 2003 and in 2006 c. find the year when the record will be 43.26 sec. round to nearest hundredth
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dumbcow
  • dumbcow
use 2 points (t,R) (0,45.9) and (40,44.7) slope = (44.7-45.9)/(40-0) = -1.2/40 = -.03 y_intercept is when t=0: (0,45.9) R(t) = -.03t + 45.9
anonymous
  • anonymous
hi dumbcow what is the ans to the other two questions b and c
dumbcow
  • dumbcow
use R(t) and substitute in t=83 and t=86 for part c 43.26 = -.03t +45.9 solve for t

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anonymous
  • anonymous
what year will the record be 43.26 sec
dumbcow
  • dumbcow
get t by itself 1) subtract 45.9 on both sides 2) divide by -.03 on both sides
anonymous
  • anonymous
I'm very confuse now
dumbcow
  • dumbcow
do you know how to solve linear equations? like 4x -2 = 10 solve for x
anonymous
  • anonymous
no i do not
dumbcow
  • dumbcow
well that would help you with this question and class im guessing... t=88 this means 88 years after 1920 =2008
anonymous
  • anonymous
that helped me thank you very much

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