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anonymous
 5 years ago
the mean of 6, 9, and 18 is equal to the mean of 12 and y. What is the value of y ?
anonymous
 5 years ago
the mean of 6, 9, and 18 is equal to the mean of 12 and y. What is the value of y ?

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nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Can you write down what the given condition is, in mathematical terms?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but what is the mean of several numbers in formula?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0You see, I'm trying to help you find the solution yourself. Where is the problem — do you know what the mean is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh sorry, the mean means average.

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Yes and for some numbers a,b,c, how do you calculate it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0show me how you work it out

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0So you don't want my help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i do but can you show me how to work it out

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0I can lead you along the path; First you have to write down those two means as formula. Of course the one for 6,9,18 can imediately be calculated completely.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Shine already worked it out but he/she didn't show us how to work it out

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0I don't understand, what your problem is... Why don't you do what I tell you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(6+9+18)/3=(12+y)/2=>y=10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you are right because you have the same answer as Shine
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