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anonymous
 5 years ago
Find an equation of the line passing through the point (6,5) and perpendicular to the line whose equation is 2y+3x=6.
anonymous
 5 years ago
Find an equation of the line passing through the point (6,5) and perpendicular to the line whose equation is 2y+3x=6.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Given equation is 2y+3x=6 = 2y=63x =y= 33/2x now we have equation of line in a form of y=mx+c slope m=3/2 prependicular slope=2/3 now equation of line is given by y=mx+b given points are (6,5) plug values we will get 5=2/3(6)+b 5=4+b b=1 now equation of line prependicular to given line is y=2/3x+1
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