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anonymous

  • 5 years ago

find the area of a rhombus wiht a perimeter of 40 and an angle of 60

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  1. anonymous
    • 5 years ago
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    area=(side length)^2 sin theta

  2. anonymous
    • 5 years ago
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    A=10^2 sin 60=50sqrt{3}

  3. anonymous
    • 5 years ago
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    Perimeter is 40, so side is 40/4=10 You know the height, 10sin(60)=5sqrt(3) Thus you can find the area!

  4. anonymous
    • 5 years ago
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    amogh..there is the square of the side length...no?

  5. anonymous
    • 5 years ago
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    Its basically side * sine of side.

  6. anonymous
    • 5 years ago
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    Which seems to be a square.

  7. anonymous
    • 5 years ago
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    its side^2 sin (angle)

  8. anonymous
    • 5 years ago
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    I wrote the same, Its side* height =side*side*sine of the side

  9. anonymous
    • 5 years ago
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    then it should be 50sqrt(3)

  10. anonymous
    • 5 years ago
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    sine of angle, iguess :S

  11. anonymous
    • 5 years ago
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    then how do i find the area

  12. anonymous
    • 5 years ago
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    uzma gave the answer to that,

  13. anonymous
    • 5 years ago
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    i posted it earlier

  14. anonymous
    • 5 years ago
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    Softball go to your previous question

  15. anonymous
    • 5 years ago
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    A trig solution: \[100\text{ Sin}\left[\frac{60}{180}\pi \right]=86.6025\]

  16. anonymous
    • 5 years ago
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    uzma got it first.

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