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anonymous
 5 years ago
find the area of a rhombus wiht a perimeter of 40 and an angle of 60
anonymous
 5 years ago
find the area of a rhombus wiht a perimeter of 40 and an angle of 60

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0area=(side length)^2 sin theta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A=10^2 sin 60=50sqrt{3}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Perimeter is 40, so side is 40/4=10 You know the height, 10sin(60)=5sqrt(3) Thus you can find the area!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amogh..there is the square of the side length...no?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its basically side * sine of side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which seems to be a square.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its side^2 sin (angle)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I wrote the same, Its side* height =side*side*sine of the side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then it should be 50sqrt(3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sine of angle, iguess :S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then how do i find the area

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uzma gave the answer to that,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Softball go to your previous question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A trig solution: \[100\text{ Sin}\left[\frac{60}{180}\pi \right]=86.6025\]
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