anonymous
  • anonymous
find the area of a rhombus wiht a perimeter of 40 and an angle of 60
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
area=(side length)^2 sin theta
anonymous
  • anonymous
A=10^2 sin 60=50sqrt{3}
anonymous
  • anonymous
Perimeter is 40, so side is 40/4=10 You know the height, 10sin(60)=5sqrt(3) Thus you can find the area!

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anonymous
  • anonymous
amogh..there is the square of the side length...no?
anonymous
  • anonymous
Its basically side * sine of side.
anonymous
  • anonymous
Which seems to be a square.
anonymous
  • anonymous
its side^2 sin (angle)
anonymous
  • anonymous
I wrote the same, Its side* height =side*side*sine of the side
anonymous
  • anonymous
then it should be 50sqrt(3)
anonymous
  • anonymous
sine of angle, iguess :S
anonymous
  • anonymous
then how do i find the area
anonymous
  • anonymous
uzma gave the answer to that,
anonymous
  • anonymous
i posted it earlier
anonymous
  • anonymous
Softball go to your previous question
anonymous
  • anonymous
A trig solution: \[100\text{ Sin}\left[\frac{60}{180}\pi \right]=86.6025\]
anonymous
  • anonymous
uzma got it first.

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