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anonymous
 5 years ago
We have 3 zeros, 0,0,0. How to gain 6 from these three zeros. Rules: only use math.
anonymous
 5 years ago
We have 3 zeros, 0,0,0. How to gain 6 from these three zeros. Rules: only use math.

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nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.2What's the difference between them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no difference only do process and gain 6 from three zeros..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't understand the question.

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.2If there is no difference between those zeros, there is also no difference between 3 and 6 zeros.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don2T mean 6 zeros i mean '6'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just use normal math acks... +,,/.... and the solution should be 6 :) got it??

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.2That depends, what you see as normal. But I guess you want to have \[6 = (0! + 0! + 0!)!\]

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0How about getting 31 exactly by using four of 4s ?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0I am able to write from 1 to 36 by exactly using four of 4. 31 is one of the thoughest one. I don't know how to get 37.

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.2Do you know that function \(\mathfrak F\) which multiplies every input by \(\frac{37}{4}\)? :D

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0:D :D Is that a Graumann function?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0G shoud come after F right?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.2Is binomial allowed?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0Like \({4\choose \sqrt{4}}\) you mean?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0Sure, even I don't use any binomial up to 36.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don'T got your question watchmath ^^ it seems like hard :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you explain me that function\[\xi\]

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0nowhereman was kidding, there is no such function :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0xd ^^ so how can i we use four4 or fours 4s??

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0Here: http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dd4b58dd95c8b0b95b558c4
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