anonymous
  • anonymous
If a 65kg woman is driving off a 10 meter platform, what is her speed as she hits the water?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
more information is required to answer this question like her initial speed(or velocity),acceleration,frictional force(if any) etc
anonymous
  • anonymous
No it isn't. Assuming no air resistance, you just use: \[v^2=u^2+2as\]Her initial vertical velocity is zero so this term disappears, you know s=10m and a=9.81ms^-2
anonymous
  • anonymous
the woman is driving off the platform..how can her inital velocity be zero?

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anonymous
  • anonymous
I agree with bendt ans its correct
anonymous
  • anonymous
Her initial vertical velocity is zero, not her horizontal velocity.
anonymous
  • anonymous
before driving off the plateform her speed is zeroo
anonymous
  • anonymous
At the instant she leaves the platform, the vertical component of her velocity vector is zero.
anonymous
  • anonymous
mmm...but isnt the final speed affected by both vertical and horizontal components?
anonymous
  • anonymous
horizontal component doesnot play any role in vertical velocity
anonymous
  • anonymous
Yes, Vids93, but that's not what the question's asking. Think of her walking off the platform.
anonymous
  • anonymous
i see the qs says what is the 'speed' as the woman hits the water!
anonymous
  • anonymous
Yes but it clearly doesn't want you to take into account the horizontal velocity because, as you said, you would need more information.
anonymous
  • anonymous
Thanks bendt..:)
anonymous
  • anonymous
No problem.
anonymous
  • anonymous
What would the u^2 stand for?
anonymous
  • anonymous
Initial velocity.
anonymous
  • anonymous
Ok thank you!

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