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anonymous
 5 years ago
If a 65kg woman is driving off a 10 meter platform, what is her speed as she hits the water?
anonymous
 5 years ago
If a 65kg woman is driving off a 10 meter platform, what is her speed as she hits the water?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0more information is required to answer this question like her initial speed(or velocity),acceleration,frictional force(if any) etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No it isn't. Assuming no air resistance, you just use: \[v^2=u^2+2as\]Her initial vertical velocity is zero so this term disappears, you know s=10m and a=9.81ms^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the woman is driving off the platform..how can her inital velocity be zero?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I agree with bendt ans its correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Her initial vertical velocity is zero, not her horizontal velocity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0before driving off the plateform her speed is zeroo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0At the instant she leaves the platform, the vertical component of her velocity vector is zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mmm...but isnt the final speed affected by both vertical and horizontal components?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0horizontal component doesnot play any role in vertical velocity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, Vids93, but that's not what the question's asking. Think of her walking off the platform.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see the qs says what is the 'speed' as the woman hits the water!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes but it clearly doesn't want you to take into account the horizontal velocity because, as you said, you would need more information.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What would the u^2 stand for?
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