Need to simplify square root of s/s^2. Answer is s-3/2 but don't know how they got it! Can someone help?

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Need to simplify square root of s/s^2. Answer is s-3/2 but don't know how they got it! Can someone help?

Mathematics
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you mean sqrt(1/s) = s - (3/2) ?
\[\sqrt{s}\div s ^{2}\]
Assuming s is in the correct domain: \[\frac{\sqrt{s}}{s^2} = s^{\frac{1}{2}}\cdot s^{-2} = s^{-\frac{3}{2}}\]

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\(\sqrt{x}=x^{1/2}\) Also \(\frac{x^a}{x^b}=x^{a-b}\) So putting those together... \[\frac{\sqrt{x}}{x^2}=\frac{x^{1/2}}{x^2}=x^{1/2 - 2}=x^{-3/2}\] Hope this helps. :)
I thought you subtracted the exponents when they were in the "divided by" form! No?
You do, I just wrote it in a different form.
Ok! I see now! I do! Thanks a bunch guys!!! thanks so much!

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