A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do I solve 4x+5y=0
3x+2y=23 by substitution?
anonymous
 5 years ago
How do I solve 4x+5y=0 3x+2y=23 by substitution?

This Question is Closed

Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it necessary by substitution? U can multiply equation (4x+5y=0) by 2 and the other equation by 5 and then substract the two. Or you can use equation(4x+5y=0) and put y= 4x/5 and put it in the second equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Method 1: 1. Multiply Eqn 1 by 2 8x+10y = 0 2. Multiply Eqn 2 by 5 15x + 10y = 115 3. Subtract these 2 equations  23x = 115 x = 5 4. Substitute x = 5 in Eqn 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank You so much for your help. :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.