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anonymous
 5 years ago
ok, here's another exponent problem! If you guys don't mind...cube root of s over s^2 = ?
anonymous
 5 years ago
ok, here's another exponent problem! If you guys don't mind...cube root of s over s^2 = ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[3]{s}\div s ^{2}\]

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0I believed this was asked just a little while ago today...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why is to the 1/3 and not positive 1/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[s ^{1/3} . s ^{2}\] = s\[s ^{5/6}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[{s^{1/3} \over s^2} = {1 \over s^{2\frac{1}{3}}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you, jgeorge! Thanks so much!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Amistre64, where in the heck have you been? I have calculus problems to solve, you know!!! ; )

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i had to do laundry; and air up my tire; put oil in the car... you know, nonmathical stuff lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, next time do those things when I DON'T need your help! Seriously, how have you been? Can you help me now with the antiderivative of that exponent you gave me? And wait a minute, why is it to the 5//6 and not 5/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it is s^5/3, then? right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and you want to derive that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Need help finding the antiderivative of this if you don't mind then. Let me try to attach an equation just to look professional, like i know what I'm doing! ; )

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no keeping secrets now lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Need to find the antid of that! I know it's ssomething. but it's the "something" i get stuck on, sort of!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[(5/3)s^{(5/3  3/3)}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5}{3 s^2 \sqrt[3]{s^2}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\(*\sqrt[3]{s}\) top and bottom to rationalise the denm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5 \sqrt[3]{s}}{3s^3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well I am trying to figure out the first step where had 5 over all that gobbledygook. I don't get that part at all!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its the same steps as derive \(x^4\)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\(\ 'exp' * x^{(exp1)}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where did the s^2 come fronm in the denominator? I see about the cube root, but not that.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lets take this one step at a time.... \[s^{(a)} \iff a*s^{a1}\] \[\frac{5}{3}s^{(\frac{5}{3}\frac{3}{3})} \iff \frac{5 s^{8/3}}{3}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5}{3s^{8/3}} \iff \frac{5}{3s^{6/3}s^{2/3}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5}{3s^2 s^{2/3}}*\frac{s^{1/3}}{s^{1/3}}=\frac{5s^(1/3)}{3s^2 s}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, I see where you are getting those numbers, but why do you have to do the 6/3 2/3 thing in the denominator in the first place? Why do you have to break it up like that? You can't just leave it? Why 2 "s" 's?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5 \sqrt[3]{s}}{3s^3}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1for the same reason why we dont leave \(\sqrt{36}\) as it is :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, but why the s^3? I though it was s^2 in the denominator! aaarrrgh!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{s.s.s.s.s.s.s.s} \iff s^2 \sqrt[3]{s^2}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{s^3 s^3 s^2} \iff \sqrt[3]{s^3}\sqrt[3]{s^3}\sqrt[3]{s^2}\] \[s.s.\sqrt[3]{s^2} \iff s^2 \sqrt[3]{s^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, go back up if you would to where I said,"ok, I see where you get those numbers, but why do you have to do the 6/3 2/3 thing in the denominator." See that post of mine? the one right before it is yours. THATS what I don't understand!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and the posts i just did explain that :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, then I am just an idiot, because I don't get it at all. What to do?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\(\frac{5}{3s^{8/3}}\) is what we get in the denominator right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1your question is about the s^(8/3) and how we play with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that 3s^8/3? It's quite small! But yes that is my question. How to play with it. But i have other things I would rather play with. Exponents AINT one of em!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Does \(s^{8/3}\) equal \(\sqrt[3]{s^8}\)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, i would have to say it does. ok, go on... please!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Does \(s^8\) mean: \(s.s.s.s.s.s.s.s\) ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Does \(s.s.s.s.s.s.s.s\) equal \((s.s.s).(s.s.s).(s.s)\) ? Does \((s.s.s).(s.s.s).(s.s) \iff s^3 s^3 s^2\) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but is there a reason you split it up like that and not like (s.s.s.s).(s.s).(s.s)?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes theres; our radical is a \(\sqrt[3]{...}\) which means we want to group these into \(s^3\) .

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and heres why: \(\sqrt[3]{s^8} \iff \sqrt[3]{s^3s^3s^2} \iff \sqrt[3]{s^3}\sqrt[3]{s^3}\sqrt[3]{s^2}\)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{s^3} = s\] \[s.s.\sqrt[3]{s^2} \iff s^2 \sqrt[3]{s^2 }\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OMGosh! Ok, so back to the problem...I don't remember where we were even!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1these are the basic steps that you tend to do in your head to avoid all the work of reproving them time and again lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe in YOUR head, but not MINE!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes, it does help to actually step thru them to gain insight ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ok so we are left with: \[\frac{5}{3s^2\sqrt[3]{s^2}}\] and thats fine but, we maybe want to get rid of the radical in the bottom part

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we 'know' \(\sqrt[3]{s^3}=s\) so we want to multily top and bttom by \(\sqrt[3]{s}\) to get rid of it in the bottom right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5 \sqrt[3]{s}}{3s^3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, if you multiply the numerator by that radical and that radical =s, why do you still have the radical sign there?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[5 * \sqrt[3]{s} = 5\sqrt[3]{s}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, but it's the cube root of s^3. That just equals s I thought?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[3s^2\sqrt[3]{s^2}*\sqrt[3]{s}\iff3s^2\sqrt[3]{s^2.s}\iff3s^2\sqrt[3]{s^3}\iff 3s^2.s\] \[\implies 3s^3 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are they all this hard? How in the heck do they expect newcomers here to calculus to know all this crap? I really don't understand! It's so hard!!!!! : (

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they expect you to have learned this in college algebra; since thats all it is

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if they have to reteach you what you should have already learned... then it gets rather ...... misses the point of dividing mathinto teachable sections lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BTW your answers are always the best and easiest to work with! As are you! Thank you so much! I am going to go and try towrok this problem...will you be around? Oh, and the college algebra thing? I got a LOW C! I couldn't do it then; I aced calc in college 20 years ago, and now don't know a thing, but could help my daughter with high school algebra II like a pro (sort of).

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1:) youre doing fine :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get the point! Do you know of a good website with the exponent rules on it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually, somehow in calc I'm getting a 97%!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1my sirttes are all books; but i know a good practie site for math: interactmath.com

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sirttes eh.... my uiniversal translator is on the fritz i think lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, what is a sirttes anyways?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it my brain cells jockeying for position lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Will you be around for some of today? Can I visit you here again if I need to?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ill be here as long as the weather holds up; im under the veranda since the libraries are closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, then again...thanks from the bottom of my heart for all your wonderful help! You're the best! Giving me all that time and patience...you're great, thanks
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