anonymous
  • anonymous
x^2-4 FIND THE HOLES ------ x+1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
is it "holes" or "poles"? if it is poles this thing has a pole at -1 because that is where the denominator is 0. i have never heard of it being called a "hole"
anonymous
  • anonymous
usually called vertical asymptote
anonymous
  • anonymous
yea vertical asymptote

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anonymous
  • anonymous
or horizontal
anonymous
  • anonymous
ok vertical asymptote set denominator = 0 and solve
anonymous
  • anonymous
so long as the numerator is not also zero there, you have a vertical asymptote
mathteacher1729
  • mathteacher1729
SeeRed -- have you graphed this function?
anonymous
  • anonymous
in this case \[\frac{(x+2)(x-2)}{x+1}\]
anonymous
  • anonymous
^yes
anonymous
  • anonymous
denominator is 0 if x = -1 so it will have a vertical asymptote there. no horizontal asymptote because the degree of the numerator is bigger than the degree of the denominator
anonymous
  • anonymous
do you need to find the 'slant' asymptote as well?
anonymous
  • anonymous
no i have the the answer. thak for your help
anonymous
  • anonymous
welcome

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