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anonymous
 5 years ago
x^24 FIND THE HOLES

x+1
anonymous
 5 years ago
x^24 FIND THE HOLES  x+1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it "holes" or "poles"? if it is poles this thing has a pole at 1 because that is where the denominator is 0. i have never heard of it being called a "hole"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0usually called vertical asymptote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea vertical asymptote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok vertical asymptote set denominator = 0 and solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so long as the numerator is not also zero there, you have a vertical asymptote

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.1SeeRed  have you graphed this function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in this case \[\frac{(x+2)(x2)}{x+1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0denominator is 0 if x = 1 so it will have a vertical asymptote there. no horizontal asymptote because the degree of the numerator is bigger than the degree of the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you need to find the 'slant' asymptote as well?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i have the the answer. thak for your help
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