## anonymous 5 years ago x^2-4 FIND THE HOLES ------ x+1

1. anonymous

is it "holes" or "poles"? if it is poles this thing has a pole at -1 because that is where the denominator is 0. i have never heard of it being called a "hole"

2. anonymous

usually called vertical asymptote

3. anonymous

yea vertical asymptote

4. anonymous

or horizontal

5. anonymous

ok vertical asymptote set denominator = 0 and solve

6. anonymous

so long as the numerator is not also zero there, you have a vertical asymptote

7. mathteacher1729

SeeRed -- have you graphed this function?

8. anonymous

in this case $\frac{(x+2)(x-2)}{x+1}$

9. anonymous

^yes

10. anonymous

denominator is 0 if x = -1 so it will have a vertical asymptote there. no horizontal asymptote because the degree of the numerator is bigger than the degree of the denominator

11. anonymous

do you need to find the 'slant' asymptote as well?

12. anonymous