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Mathsadness
 5 years ago
For the domain, 2≤x≤3, what is the range of the function f(x)=2x+1 ?
Mathsadness
 5 years ago
For the domain, 2≤x≤3, what is the range of the function f(x)=2x+1 ?

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the smallest the absolute value of something can be is 0, so you know the range starts at 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0replace x by 3 and get 7, so that is the largest it can be. range : {0,7}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess it is worth mentioning that you should also replace x by 2, but in that case you only get 3, which is smaller than 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when x = 1/2, f(x) = 0 when x = 3, f(x) = 7; hence the range 0 to 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can someone help me with my question ill give you a medal.... PLEASE!!!

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0NOTE: we can't just assume the range starts at zero because it's an absolute value function. What if we specified the domain to be (10,11)? Here is a graph. remember RANGE = "lowest value of y to highest value of y that the graph attains". Hope this helps. :)
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