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Mathsadness

  • 5 years ago

For the domain, -2≤x≤3, what is the range of the function f(x)=|2x+1| ?

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    the smallest the absolute value of something can be is 0, so you know the range starts at 0

  3. anonymous
    • 5 years ago
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    replace x by 3 and get 7, so that is the largest it can be. range : {0,7}

  4. anonymous
    • 5 years ago
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    i guess it is worth mentioning that you should also replace x by -2, but in that case you only get 3, which is smaller than 7

  5. anonymous
    • 5 years ago
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    when x = 1/2, f(x) = 0 when x = 3, f(x) = 7; hence the range 0 to 7

  6. anonymous
    • 5 years ago
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    can someone help me with my question ill give you a medal.... PLEASE!!!

  7. mathteacher1729
    • 5 years ago
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    NOTE: we can't just assume the range starts at zero because it's an absolute value function. What if we specified the domain to be (10,11)? Here is a graph. remember RANGE = "lowest value of y to highest value of y that the graph attains". Hope this helps. :)

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