anonymous
  • anonymous
Find the exact value of the following expression (multiple choice)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://tigger.uic.edu/~calkafka/spring2011math121practiceexam3.pdf - number 17
anonymous
  • anonymous
method or answers?
anonymous
  • anonymous
method. i'll figure out the answer from the method..that way, i learn the method and figure the answer

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anonymous
  • anonymous
or calculator?
anonymous
  • anonymous
k
anonymous
  • anonymous
number 1. think of a number (angle) between 0 and pi whose cosine is \[\frac{\sqrt{3}}{2}\]
anonymous
  • anonymous
look at trig cheat sheet here http://tutorial.math.lamar.edu/cheat_table.aspx if you do not remember
mathteacher1729
  • mathteacher1729
Drawing pictures is SUPER helpful. The trig sheet Satellite mentioned is also very nice. :)
anonymous
  • anonymous
oh i only nueed help on number 17. thanks though
anonymous
  • anonymous
aaahhhhhhhh
mathteacher1729
  • mathteacher1729
Still,l a pic would help. Lemmie sketch out one... brb.
anonymous
  • anonymous
addition angle formula: \[sin(a+b)=sin(a)cos(b)+cos(a)sin(b)\]
mathteacher1729
  • mathteacher1729
You won't even have to do that, I think, cuz you have to do the inverse sin & cos stuff inside the main sin argument.
anonymous
  • anonymous
thats what i thought..at math teacher
anonymous
  • anonymous
i just dont know how to go about solving it
anonymous
  • anonymous
typeset is goofy but i assume it means \[sin(sin^{-1}(\frac{2}{3}) + cos^{-1}(\frac{1}{3}))\]
anonymous
  • anonymous
yuppers. thats what it means
anonymous
  • anonymous
put \[a=sin^{-1}(\frac{2}{3}), b=cos^{-1}(\frac{1}{3})\]
anonymous
  • anonymous
use formula above. you aready know \[sin(sin^{-1}(\frac{2}{3}))=\frac{2}{3}\]
anonymous
  • anonymous
you need \[cos^{-1}(\frac{2}{3})=\frac{\sqrt{5}}{3}\] by pythagoras
anonymous
  • anonymous
oops typo
anonymous
  • anonymous
you need \[cos(sin^{-1}(\frac{2}{3}))=\frac{\sqrt{5}}{3}\]
anonymous
  • anonymous
by pythagoras.
mathteacher1729
  • mathteacher1729
Here is the first part.
1 Attachment
anonymous
  • anonymous
ahh the pythagorean thm
anonymous
  • anonymous
what math teacher said. you only need to find \[sin(cos^{-1}(\frac{1}{3}))=\frac{\sqrt{2}}{3}\]
anonymous
  • anonymous
now you have everything you need to plug in to the "addition angle" formula
anonymous
  • anonymous
but i think you must use the formula now. you have all 4 numbers that you need. \[sin(a)=\frac{2}{3}\] \[cos(a)=\frac{\sqrt{5}}{3}\]
anonymous
  • anonymous
\[sin(b)=\frac{\sqrt{2}}{3}\] \[cos(b)=\frac{1}{3}\]
anonymous
  • anonymous
write out the formula, substitute the numbers, and be done.
anonymous
  • anonymous
right. gimme a sec.
anonymous
  • anonymous
whoooooooooooops
anonymous
  • anonymous
\[sin(b)=\frac{\sqrt{8}}{3}\]
anonymous
  • anonymous
fraid both math teacher and i made a mistake.
anonymous
  • anonymous
its okay. i'm still working on it. thanks
anonymous
  • anonymous
if you look at the picture math teachers sent unfortunately the second triangle is wrong. adjacent side is 1, hypotenuse is 3, opposite side should be \[{\sqrt{8}}=2\sqrt{2}\]
anonymous
  • anonymous
get \[\frac{2}{3}\times \frac{\sqrt{5}}{3}+\frac{1}{3}\times \frac{2\sqrt{2}}{3}\]
anonymous
  • anonymous
is the answer for number 17 "A"? thats what i'm getting. http://tigger.uic.edu/~calkafka/spring2011math121practiceexam3.pdf
mathteacher1729
  • mathteacher1729
Oh my gosh, I can't believe I did that. :( here is the corrected version.
anonymous
  • anonymous
dont worry mathteacher. satellite clarified. i'm debating on whether its A or B for number 17 in the link i posted
anonymous
  • anonymous
A yes!
anonymous
  • anonymous
SWEET! thanky you so much!
anonymous
  • anonymous
welcome

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