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anonymous
 5 years ago
Find the exact value of the following expression (multiple choice)
anonymous
 5 years ago
Find the exact value of the following expression (multiple choice)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://tigger.uic.edu/~calkafka/spring2011math121practiceexam3.pdf  number 17

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0method. i'll figure out the answer from the method..that way, i learn the method and figure the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0number 1. think of a number (angle) between 0 and pi whose cosine is \[\frac{\sqrt{3}}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0look at trig cheat sheet here http://tutorial.math.lamar.edu/cheat_table.aspx if you do not remember

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0Drawing pictures is SUPER helpful. The trig sheet Satellite mentioned is also very nice. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i only nueed help on number 17. thanks though

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0Still,l a pic would help. Lemmie sketch out one... brb.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0addition angle formula: \[sin(a+b)=sin(a)cos(b)+cos(a)sin(b)\]

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0You won't even have to do that, I think, cuz you have to do the inverse sin & cos stuff inside the main sin argument.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i thought..at math teacher

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont know how to go about solving it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0typeset is goofy but i assume it means \[sin(sin^{1}(\frac{2}{3}) + cos^{1}(\frac{1}{3}))\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yuppers. thats what it means

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put \[a=sin^{1}(\frac{2}{3}), b=cos^{1}(\frac{1}{3})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use formula above. you aready know \[sin(sin^{1}(\frac{2}{3}))=\frac{2}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need \[cos^{1}(\frac{2}{3})=\frac{\sqrt{5}}{3}\] by pythagoras

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need \[cos(sin^{1}(\frac{2}{3}))=\frac{\sqrt{5}}{3}\]

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0Here is the first part.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh the pythagorean thm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what math teacher said. you only need to find \[sin(cos^{1}(\frac{1}{3}))=\frac{\sqrt{2}}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you have everything you need to plug in to the "addition angle" formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i think you must use the formula now. you have all 4 numbers that you need. \[sin(a)=\frac{2}{3}\] \[cos(a)=\frac{\sqrt{5}}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[sin(b)=\frac{\sqrt{2}}{3}\] \[cos(b)=\frac{1}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0write out the formula, substitute the numbers, and be done.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[sin(b)=\frac{\sqrt{8}}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fraid both math teacher and i made a mistake.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its okay. i'm still working on it. thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you look at the picture math teachers sent unfortunately the second triangle is wrong. adjacent side is 1, hypotenuse is 3, opposite side should be \[{\sqrt{8}}=2\sqrt{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0get \[\frac{2}{3}\times \frac{\sqrt{5}}{3}+\frac{1}{3}\times \frac{2\sqrt{2}}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the answer for number 17 "A"? thats what i'm getting. http://tigger.uic.edu/~calkafka/spring2011math121practiceexam3.pdf

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0Oh my gosh, I can't believe I did that. :( here is the corrected version.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont worry mathteacher. satellite clarified. i'm debating on whether its A or B for number 17 in the link i posted

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SWEET! thanky you so much!
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