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anonymous

  • 5 years ago

Is sin 15 degrees is the same as pi/12? I'm suppose to find the exact value of the expression. multiple choice hw

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  1. amistre64
    • 5 years ago
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    pi/3 = 60 pi/6 = 30 pi/12 = 15

  2. amistre64
    • 5 years ago
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    180/3 = 60 180/6 = 30 180/12 = 15

  3. anonymous
    • 5 years ago
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    so I got that part right. thanks! ......please continue explanation

  4. anonymous
    • 5 years ago
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    amistre amistre amistre

  5. amistre64
    • 5 years ago
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    sin(15) = sin(45-30)

  6. anonymous
    • 5 years ago
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    \[\frac{\pi}{3}\] is not more 60 than 0 is 32

  7. amistre64
    • 5 years ago
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    sin(a-b) = sinacosb-sinbcosa

  8. anonymous
    • 5 years ago
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    0 degrees Celsius is the same temperature as 32 degrees F, but they are by no means the same number!

  9. amistre64
    • 5 years ago
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    pi 180 ---*---- = 60 3 pi

  10. anonymous
    • 5 years ago
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    true but that hardly means that \[\pi = 180\] \[\pi\] is a number close to 3, and 180 is many times bigger

  11. amistre64
    • 5 years ago
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    sin(15) = sin(45)cos(30) - sin(30)cos(45)

  12. amistre64
    • 5 years ago
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    when converting between degrees and radians; pi = 180

  13. amistre64
    • 5 years ago
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    just as 2pi = 360

  14. anonymous
    • 5 years ago
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    the point is that an angle measured is 15 degrees is the same as an angle measured in \[\frac{\pi}{12}\] radians

  15. anonymous
    • 5 years ago
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    i will be quiet now

  16. anonymous
    • 5 years ago
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    mmm. i think i understand. is the exact value squareroot2 ( squareroot 3 - 1) over 4?

  17. anonymous
    • 5 years ago
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    thank you amistre and satellite! ..just please correct my answer if i'm wrong

  18. amistre64
    • 5 years ago
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    sin(15) = \(\frac{1}{\sqrt{2}}\frac{\sqrt{3}}{2}-\frac{1}{2}\frac{1}{\sqrt{2}}\)

  19. amistre64
    • 5 years ago
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    sin(15) = \(\frac{\sqrt{6}}{2}-\frac{\sqrt{2}}{2}\)

  20. amistre64
    • 5 years ago
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    over 4 is right

  21. amistre64
    • 5 years ago
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    \[\sin(15)=\frac{\sqrt{6}-\sqrt{2}}{4}\] IF I DID IT RIGHT

  22. amistre64
    • 5 years ago
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    caps stuck lol

  23. anonymous
    • 5 years ago
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    nice latex too!

  24. amistre64
    • 5 years ago
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    i think i missed it somewhere

  25. amistre64
    • 5 years ago
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    \[sin(15) = sin(45)cos(30) - sin(30)cos(45)\] \[{\sqrt{2} \over 2}.{\sqrt{3}\over 2}-{1 \over 2}{\sqrt{2}\over 2}\] \[{\sqrt{6}\over 4}-{\sqrt{2}\over4}\]

  26. anonymous
    • 5 years ago
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    thank u i'm doing it on paper..ur much faster

  27. amistre64
    • 5 years ago
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    \[\sqrt{6}-\sqrt{2} \over 4\]

  28. amistre64
    • 5 years ago
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    this an take a few forms; all that equal the same thing but look different based upon how you went thru the stuff

  29. amistre64
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=sin%2815%29

  30. amistre64
    • 5 years ago
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    im right lol

  31. anonymous
    • 5 years ago
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    WOW THANKS!

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