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anonymous

  • 5 years ago

Amistre64, it's me again. Need help with an exponent again!

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  1. amistre64
    • 5 years ago
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    didja try yelling at it?

  2. anonymous
    • 5 years ago
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    jI even grounded it and took away it's cell phone and it won't cooperate! I can't understand...it works with my 15 year old daughter!

  3. anonymous
    • 5 years ago
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    \[-3/2\times 2^{-2/9}\]

  4. anonymous
    • 5 years ago
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    dont punish them it makes it worse. They now think math is bad if you truly want to help arrange extra help and talk to the teacher

  5. anonymous
    • 5 years ago
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    Did you see my expression I need to solve?

  6. amistre64
    • 5 years ago
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    i see it

  7. amistre64
    • 5 years ago
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    we wanna derive it?

  8. anonymous
    • 5 years ago
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    No I need to figure out what it's = to.

  9. anonymous
    • 5 years ago
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    2^-2/9 equals what?

  10. amistre64
    • 5 years ago
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    \[\frac{-3}{2*2^{2/9}}\]

  11. amistre64
    • 5 years ago
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    \[\frac{-3}{2^{(9/9 + 2/9)}}\]

  12. amistre64
    • 5 years ago
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    we good so far?

  13. anonymous
    • 5 years ago
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    yes, I got that far. I know that answer, but what i got wasn't right according to them Like they know any better! Who are they to tell me I am always wrong!?

  14. anonymous
    • 5 years ago
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    ; )

  15. amistre64
    • 5 years ago
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    :) \[\frac{-3}{2^{11/9}}\] \[\frac{-3}{\sqrt[9]{2^{11}}}\]

  16. amistre64
    • 5 years ago
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    \[2^{11} \iff 2^{9}*2^{2}\] \[\sqrt[9]{2^9.2^2}\iff \sqrt[9]{2^9}.\sqrt[9]{2^2}\] \[\frac{-3}{2\sqrt[9]{2^2}}\]

  17. amistre64
    • 5 years ago
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    \[\sqrt[9]{2^4}*\sqrt[9]{2^5} = \sqrt[9]{2^9}\iff 2\] right?

  18. anonymous
    • 5 years ago
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    yes, I remember that one from the s thing earlier! Yay me!

  19. amistre64
    • 5 years ago
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    \[\frac{-3}{2\sqrt[9]{2^4}}*\frac{\sqrt[9]{2^5}}{\sqrt[9]{2^5}} = \frac{-3\sqrt[9]{64}}{4}\]

  20. amistre64
    • 5 years ago
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    i typoed it dint i lol

  21. amistre64
    • 5 years ago
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    9rt(2^2) not equal 9rt(2^4) lol

  22. anonymous
    • 5 years ago
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    Actually we lucked out cuz they are leaving the radical in the denominator! The answer to the whole problem is cbrt 2 - 3/2ninth root of 4, just what you said! I am not surprised you got it right!

  23. amistre64
    • 5 years ago
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    yay!! i was dreading having to retype thaqt lol

  24. anonymous
    • 5 years ago
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    \[\sqrt[3]{2}- 3/2\sqrt[9]{4}\]

  25. anonymous
    • 5 years ago
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    Again and again and again, thank you.

  26. amistre64
    • 5 years ago
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    yw :)

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