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## anonymous 5 years ago Amistre64, it's me again. Need help with an exponent again!

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1. amistre64

didja try yelling at it?

2. anonymous

jI even grounded it and took away it's cell phone and it won't cooperate! I can't understand...it works with my 15 year old daughter!

3. anonymous

$-3/2\times 2^{-2/9}$

4. anonymous

dont punish them it makes it worse. They now think math is bad if you truly want to help arrange extra help and talk to the teacher

5. anonymous

Did you see my expression I need to solve?

6. amistre64

i see it

7. amistre64

we wanna derive it?

8. anonymous

No I need to figure out what it's = to.

9. anonymous

2^-2/9 equals what?

10. amistre64

$\frac{-3}{2*2^{2/9}}$

11. amistre64

$\frac{-3}{2^{(9/9 + 2/9)}}$

12. amistre64

we good so far?

13. anonymous

yes, I got that far. I know that answer, but what i got wasn't right according to them Like they know any better! Who are they to tell me I am always wrong!?

14. anonymous

; )

15. amistre64

:) $\frac{-3}{2^{11/9}}$ $\frac{-3}{\sqrt[9]{2^{11}}}$

16. amistre64

$2^{11} \iff 2^{9}*2^{2}$ $\sqrt[9]{2^9.2^2}\iff \sqrt[9]{2^9}.\sqrt[9]{2^2}$ $\frac{-3}{2\sqrt[9]{2^2}}$

17. amistre64

$\sqrt[9]{2^4}*\sqrt[9]{2^5} = \sqrt[9]{2^9}\iff 2$ right?

18. anonymous

yes, I remember that one from the s thing earlier! Yay me!

19. amistre64

$\frac{-3}{2\sqrt[9]{2^4}}*\frac{\sqrt[9]{2^5}}{\sqrt[9]{2^5}} = \frac{-3\sqrt[9]{64}}{4}$

20. amistre64

i typoed it dint i lol

21. amistre64

9rt(2^2) not equal 9rt(2^4) lol

22. anonymous

Actually we lucked out cuz they are leaving the radical in the denominator! The answer to the whole problem is cbrt 2 - 3/2ninth root of 4, just what you said! I am not surprised you got it right!

23. amistre64

yay!! i was dreading having to retype thaqt lol

24. anonymous

$\sqrt[3]{2}- 3/2\sqrt[9]{4}$

25. anonymous

Again and again and again, thank you.

26. amistre64

yw :)

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