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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first one is 15
the other is J 3

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Other answers:

can u show me step?
hoe u get 3 and 15
for the first one: log base 4 of 4^15 simply says: what power do you raise 4 to in order to get 4^15.
And so, obviously if you raise 4 to the 15th power, you get 4^15
\[\text{Log}[2,9x+5]=2+\text{Log}\left[2,x^2-1\right] \]\[\text{Log}[2,9x+5]-\text{Log}[2,x{}^{\wedge}2-1]= 2 \]\[\text{Log}\left[\frac{a}{b}\right]\text{= }\text{Log}[a]-\text{Log}[b]\]\[\text{Log}\left[2,\frac{9x+5}{x^2-1}\right]=2\]\[(\text{Log}[b,x]=k )\to \left(b^k= x\right) \]\[2^2-\frac{9x+5}{x^2-1}=0\]\[\frac{-9-9 x+4 x^2}{-1+x^2}=0 \]\[\frac{((-3+x) (3+4 x))}{-1+x^2}=0\]\[x=3 \]

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