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anonymous

  • 5 years ago

Sketch the graph of f and use it to find the domain, range, and to determine whether the function is one-to-one. f(x)=root16-x^2

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  1. amistre64
    • 5 years ago
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    \[\sqrt{16-x^2}\] is this the equation?

  2. anonymous
    • 5 years ago
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    Yes.

  3. amistre64
    • 5 years ago
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    the graph looks like angel wings.... going off in both directions

  4. amistre64
    • 5 years ago
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    its not a one to one function

  5. amistre64
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=sqrt%2816-x^2%29 lol... ok, not angel wings, but still not one to one

  6. anonymous
    • 5 years ago
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    it is the upper half of a circle with radius 4

  7. anonymous
    • 5 years ago
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    the equation for a circle centered at the origin with radius 4 is \[x^2+y^2=4^2\]

  8. anonymous
    • 5 years ago
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    Yeah, that's what I have on my calculator. I don't remember how to do the rest though....

  9. anonymous
    • 5 years ago
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    if you solve this equation for y you get \[y=\pm\sqrt{1-x^2}\]

  10. anonymous
    • 5 years ago
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    excuse me i mean \[y=\pm\sqrt{16-x^2}\]

  11. anonymous
    • 5 years ago
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    if you only take the positive part you are getting just the stuff above the x axis.

  12. anonymous
    • 5 years ago
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    it is in fact a one to one funciton

  13. anonymous
    • 5 years ago
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    Okay, that makes sense why it only shows up half on my graph.

  14. anonymous
    • 5 years ago
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    oops no it isn't sorry

  15. anonymous
    • 5 years ago
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    doesn't pass horizontal line test.

  16. amistre64
    • 5 years ago
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    when x = -4 OR +4 we get the same y

  17. anonymous
    • 5 years ago
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    domain is [-4,4] range is [0,4]

  18. anonymous
    • 5 years ago
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    of course i was being stupid

  19. myininaya
    • 5 years ago
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    satellite!

  20. anonymous
    • 5 years ago
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    55 to go i am in awe. but might have to wait until tomorrow yes?

  21. anonymous
    • 5 years ago
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    hello myininaya how goes it?

  22. amistre64
    • 5 years ago
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    maybe, with the holidays its hard to get good clickers lol

  23. anonymous
    • 5 years ago
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    This is true, lol. Thanks guys<333

  24. myininaya
    • 5 years ago
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    i need help this guy is totally confusing me about stuff i dont what the frick hes talking about

  25. anonymous
    • 5 years ago
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    yeah really. who does math on memorial day?

  26. anonymous
    • 5 years ago
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    what question?

  27. anonymous
    • 5 years ago
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    I do, apparently :P

  28. myininaya
    • 5 years ago
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    follow me

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