Sketch the graph of f and use it to find the domain, range, and to determine whether the function is one-to-one. f(x)=root16-x^2

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Sketch the graph of f and use it to find the domain, range, and to determine whether the function is one-to-one. f(x)=root16-x^2

Mathematics
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\[\sqrt{16-x^2}\] is this the equation?
Yes.
the graph looks like angel wings.... going off in both directions

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Other answers:

its not a one to one function
http://www.wolframalpha.com/input/?i=sqrt%2816-x^2%29 lol... ok, not angel wings, but still not one to one
it is the upper half of a circle with radius 4
the equation for a circle centered at the origin with radius 4 is \[x^2+y^2=4^2\]
Yeah, that's what I have on my calculator. I don't remember how to do the rest though....
if you solve this equation for y you get \[y=\pm\sqrt{1-x^2}\]
excuse me i mean \[y=\pm\sqrt{16-x^2}\]
if you only take the positive part you are getting just the stuff above the x axis.
it is in fact a one to one funciton
Okay, that makes sense why it only shows up half on my graph.
oops no it isn't sorry
doesn't pass horizontal line test.
when x = -4 OR +4 we get the same y
domain is [-4,4] range is [0,4]
of course i was being stupid
satellite!
55 to go i am in awe. but might have to wait until tomorrow yes?
hello myininaya how goes it?
maybe, with the holidays its hard to get good clickers lol
This is true, lol. Thanks guys<333
i need help this guy is totally confusing me about stuff i dont what the frick hes talking about
yeah really. who does math on memorial day?
what question?
I do, apparently :P
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