anonymous
  • anonymous
Determine the derivative of this: y = tan^2(x^3)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
How do we use the chain rule here?
anonymous
  • anonymous
first you get 3x^2 from x^3 than u do tan^2 that is 2tan^2(x^3) than tan that is sec^2(x^3)
anonymous
  • anonymous
so the answer is 6x^2 tan^2(x^3) sec^2(x^3)

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anonymous
  • anonymous
hoops not right tan^2 bit is 2tan(x^3)
anonymous
  • anonymous
6x^2 tan(x^3) sec^2(x^3)
anonymous
  • anonymous
hope it is clear
anonymous
  • anonymous
\[\tan ^2(x^3)\] <-- would you mind doing it in this format.
anonymous
  • anonymous
\[y' = 2(tanx)(\sec^2x)(x^3)(3x^2)\]

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