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anonymous
 5 years ago
How can I finish this problem?
m<JLN = 1/2 (m arc JN  m arc KM)
m<JLN = 1/2 (x^2 + 8x  20)
4x = 1/2 (x^2+8x20)
x^2 / x = 20 / x
anonymous
 5 years ago
How can I finish this problem? m<JLN = 1/2 (m arc JN  m arc KM) m<JLN = 1/2 (x^2 + 8x  20) 4x = 1/2 (x^2+8x20) x^2 / x = 20 / x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0unless we cross multiply the equation, so that it it becomes an equation where i have to find the √ of 20...

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.1\[4x = 1/2 (x^2+8x20)\] now distribute the 1/2.. \[4x = 1/2 x^2+4x10\] now subtract 4x from both sides \[0 = 1/2 x^210\] now add 10 to both sides \[10 = 1/2x^2\] See what happened there? :) You should be able to fix it from here.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank You Thank You Thank You!!!! You are a life saver!
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