anonymous
  • anonymous
is my work correct ? here is the problem: tan(arccos(-1/2)+arccos(2/3)) let A=arccos(-1/2) let A=arccos(2/3) tan(A+A)=tan(2A) tan(2A)=2tanA/1-tan^2A =2(-√3)/(1-(-√3)^2 =-2√3/1+3 =-2√3/4 =-√3/2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Owlfred
  • Owlfred
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
anonymous
  • anonymous
you can't call two different things the same variable and then add them like they are the same.
anonymous
  • anonymous
there is an identity for tan(A+B) though

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thats what i thought. but when i did it as tan(A+B) which would be tanA+tanb/1-tanAtanB it did not correspond with the answer my teacher gave which is -√3/3.
anonymous
  • anonymous
I think -sqrt(3)/3 is incorrect
anonymous
  • anonymous
what did you get?
anonymous
  • anonymous
-9√3+8√5/-13
anonymous
  • anonymous
maple is saying that isn't right. Let me work the problem.. one sec.
anonymous
  • anonymous
ok i got (-9sqrt(3)+8sqrt(5))/(-11)
anonymous
  • anonymous
thats what maple got too
anonymous
  • anonymous
ok so my numerator is right but my denominator is wrong. can you explain how you got the denominator?
anonymous
  • anonymous
my denominator was initially 1+sqrt(3)*sqrt(5)/2, so i multiplied top and bottom by the conjugate: then in the denominator you get 1-15/4. In the numerator there was a common factor of 1/4 so i multiplied the denominator by 4: 4-15=-11
anonymous
  • anonymous
ohhh never mind i got it. thanks soo much for your help!!!
anonymous
  • anonymous
you're welcome :)
anonymous
  • anonymous
are you a musician?
anonymous
  • anonymous
yeah i play the cello&piano and i can carry a tune =) also how do i give you a medal for your answer?
anonymous
  • anonymous
oh if you want you click "good answer" in line with my name on one of my posts: I play classical/jazz violin and guitar. I like cello and piano a lot.
anonymous
  • anonymous
ohh thats great ! nice to meet a fellow musician =)
anonymous
  • anonymous
well good luck with your math, talk to you later
anonymous
  • anonymous
thank you !
anonymous
  • anonymous
oh ok i got that. could you have used the quadratic formula to solve the equation?

Looking for something else?

Not the answer you are looking for? Search for more explanations.