is my work correct ? here is the problem: tan(arccos(-1/2)+arccos(2/3)) let A=arccos(-1/2) let A=arccos(2/3) tan(A+A)=tan(2A) tan(2A)=2tanA/1-tan^2A =2(-√3)/(1-(-√3)^2 =-2√3/1+3 =-2√3/4 =-√3/2

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is my work correct ? here is the problem: tan(arccos(-1/2)+arccos(2/3)) let A=arccos(-1/2) let A=arccos(2/3) tan(A+A)=tan(2A) tan(2A)=2tanA/1-tan^2A =2(-√3)/(1-(-√3)^2 =-2√3/1+3 =-2√3/4 =-√3/2

Mathematics
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Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
you can't call two different things the same variable and then add them like they are the same.
there is an identity for tan(A+B) though

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thats what i thought. but when i did it as tan(A+B) which would be tanA+tanb/1-tanAtanB it did not correspond with the answer my teacher gave which is -√3/3.
I think -sqrt(3)/3 is incorrect
what did you get?
-9√3+8√5/-13
maple is saying that isn't right. Let me work the problem.. one sec.
ok i got (-9sqrt(3)+8sqrt(5))/(-11)
thats what maple got too
ok so my numerator is right but my denominator is wrong. can you explain how you got the denominator?
my denominator was initially 1+sqrt(3)*sqrt(5)/2, so i multiplied top and bottom by the conjugate: then in the denominator you get 1-15/4. In the numerator there was a common factor of 1/4 so i multiplied the denominator by 4: 4-15=-11
ohhh never mind i got it. thanks soo much for your help!!!
you're welcome :)
are you a musician?
yeah i play the cello&piano and i can carry a tune =) also how do i give you a medal for your answer?
oh if you want you click "good answer" in line with my name on one of my posts: I play classical/jazz violin and guitar. I like cello and piano a lot.
ohh thats great ! nice to meet a fellow musician =)
well good luck with your math, talk to you later
thank you !
oh ok i got that. could you have used the quadratic formula to solve the equation?

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