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anonymous

  • 5 years ago

Find 3 consecutive even integers such that the square of the largest exceeds the sum of the quarters of the squares of the other two by 12

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  1. mathteacher1729
    • 5 years ago
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    Wow, this is a complex statement. How do you feel with simpler problems of this nature? "The sum of three consecutive integers is 12" for example. or "The sum of two consecutive odd numbers is 16" There is quite a bit to break apart in this prob, that's why I ask.

  2. anonymous
    • 5 years ago
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    I am lost on integers

  3. mathteacher1729
    • 5 years ago
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    Oh, ok. Then any explanation of this problem will probably seem way too confusing. Let's start with the ones I wrote instead. Those are a bit simpler, and will help build up to this problem.

  4. mathteacher1729
    • 5 years ago
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    An integer is a kind of number. It's a whole number which can be positive or negative. Also, zero is an integer. ... -3 , -2, -1, 0, 1, 2, 3, ... are all integers.

  5. mathteacher1729
    • 5 years ago
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    Do you know what "consecutive" means?

  6. anonymous
    • 5 years ago
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    yes in a row ie 12 13 14

  7. myininaya
    • 5 years ago
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    x is the first even integer x+2 is the next even integer x+4 is the third even integer (x+4)^2=1/4*(x^2+(x+2)^2)+12

  8. myininaya
    • 5 years ago
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    x^2+8x+16=1/4*(x^2+x^2+4x+4)+12 x^2+8x+16=1/4*(2x^2+4x+4)+12 x^2+8x+16=x^2/2+x+1+12 x^2+8x+16=x^2/2+x+13 -x^2/2+7x+3=0 x^2-14x-6=0 this does not give us integer so maybe i misread the question

  9. anonymous
    • 5 years ago
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    To me it seems many of these questions are not well written which doesn't help

  10. myininaya
    • 5 years ago
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    the question seems really confusing lol

  11. anonymous
    • 5 years ago
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    lol tell me about it. They are ALL that way

  12. mathteacher1729
    • 5 years ago
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    Myininaya -- what if we start with x = 1 :-p You need to do 2n , 2n+2 , 2n+4. Also, this is a complex problem. Is this a test or HW question?

  13. mathteacher1729
    • 5 years ago
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    It drives me mad when profs put questions on the test which are WAY MORE DIFFICULT and NOTHING LIKE the HW problems they assign or the problems they go over in class.

  14. anonymous
    • 5 years ago
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    yeah, thanks for help. Is homework

  15. myininaya
    • 5 years ago
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    it doesn't matter what kindof question this is this is an algebra class lol this is ridiculous for an algebra class

  16. anonymous
    • 5 years ago
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    THANK YOU!!! I agree

  17. myininaya
    • 5 years ago
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    unless it is a bonus question

  18. mathteacher1729
    • 5 years ago
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    Well in the proper context, it's not a ridiculous question. If this was a question at the end of the chapter on how to interpret word problems for an advanced algebra class, yeah it makes sense. Is this a TYPICAL hw problem? Like, are all the others similar in complexity to it?

  19. anonymous
    • 5 years ago
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    This is PRE algebra. They are all this way

  20. anonymous
    • 5 years ago
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    and not a bonus question regular one

  21. myininaya
    • 5 years ago
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    i haven't gave up yet you wrote the question exactly as it appears in the book right?

  22. anonymous
    • 5 years ago
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    yes

  23. myininaya
    • 5 years ago
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    others or other?

  24. myininaya
    • 5 years ago
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    nvm

  25. anonymous
    • 5 years ago
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    I cant wait for this class to be over

  26. myininaya
    • 5 years ago
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    i don't see how it isn't (x+4)^2=1/4*x^2+1/4*(x+2)^2+12 x^2+8x+16=1/4*x^2+1/4*(x^2+4x+4)+12 x^2+8x+16=1/4*x^2+1/4*x^2+x+1+12 x^2+8x+16=1/2*x^2+x+13 1/2*x^2+7x+3=0 x^2+14x+6=0 but like i said before this does not give an integer for x so i just don't get the question i guess mathteacher will you please tell me what is wrong with this

  27. anonymous
    • 5 years ago
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    I appreciate your help

  28. myininaya
    • 5 years ago
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    i tried lol i can't see this problem any other way what i have above is what it means to me maybe i'm making a mistake in the translation, but i don't see where or how so sorry

  29. anonymous
    • 5 years ago
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    No need to be sorry, I appreciate it.

  30. mathteacher1729
    • 5 years ago
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    Ok, got something, but I think there might be an issue with the wording here. Lemmie know what you think.

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  31. myininaya
    • 5 years ago
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    that is exactly how i set my up exept we introduced are variables differently

  32. anonymous
    • 5 years ago
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    makes more sense than what I got

  33. myininaya
    • 5 years ago
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    hey that is 12 right not 15?

  34. anonymous
    • 5 years ago
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    yes

  35. myininaya
    • 5 years ago
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    ok i have discussed this problem with others and they also agree there are no such integers i'm just shocked they would have given you a problem that you cannot find the solution to so just say there are no such integers

  36. anonymous
    • 5 years ago
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    ok thank you

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