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Wow, this is a complex statement. How do you feel with simpler problems of this nature? "The sum of three consecutive integers is 12" for example. or "The sum of two consecutive odd numbers is 16" There is quite a bit to break apart in this prob, that's why I ask.
I am lost on integers
Oh, ok. Then any explanation of this problem will probably seem way too confusing. Let's start with the ones I wrote instead. Those are a bit simpler, and will help build up to this problem.
An integer is a kind of number. It's a whole number which can be positive or negative. Also, zero is an integer. ... -3 , -2, -1, 0, 1, 2, 3, ... are all integers.
Do you know what "consecutive" means?
yes in a row ie 12 13 14
x is the first even integer x+2 is the next even integer x+4 is the third even integer (x+4)^2=1/4*(x^2+(x+2)^2)+12
x^2+8x+16=1/4*(x^2+x^2+4x+4)+12 x^2+8x+16=1/4*(2x^2+4x+4)+12 x^2+8x+16=x^2/2+x+1+12 x^2+8x+16=x^2/2+x+13 -x^2/2+7x+3=0 x^2-14x-6=0 this does not give us integer so maybe i misread the question
To me it seems many of these questions are not well written which doesn't help
the question seems really confusing lol
lol tell me about it. They are ALL that way
Myininaya -- what if we start with x = 1 :-p You need to do 2n , 2n+2 , 2n+4. Also, this is a complex problem. Is this a test or HW question?
It drives me mad when profs put questions on the test which are WAY MORE DIFFICULT and NOTHING LIKE the HW problems they assign or the problems they go over in class.
yeah, thanks for help. Is homework
it doesn't matter what kindof question this is this is an algebra class lol this is ridiculous for an algebra class
THANK YOU!!! I agree
unless it is a bonus question
Well in the proper context, it's not a ridiculous question. If this was a question at the end of the chapter on how to interpret word problems for an advanced algebra class, yeah it makes sense. Is this a TYPICAL hw problem? Like, are all the others similar in complexity to it?
This is PRE algebra. They are all this way
and not a bonus question regular one
i haven't gave up yet you wrote the question exactly as it appears in the book right?
others or other?
I cant wait for this class to be over
i don't see how it isn't (x+4)^2=1/4*x^2+1/4*(x+2)^2+12 x^2+8x+16=1/4*x^2+1/4*(x^2+4x+4)+12 x^2+8x+16=1/4*x^2+1/4*x^2+x+1+12 x^2+8x+16=1/2*x^2+x+13 1/2*x^2+7x+3=0 x^2+14x+6=0 but like i said before this does not give an integer for x so i just don't get the question i guess mathteacher will you please tell me what is wrong with this
I appreciate your help
i tried lol i can't see this problem any other way what i have above is what it means to me maybe i'm making a mistake in the translation, but i don't see where or how so sorry
No need to be sorry, I appreciate it.
that is exactly how i set my up exept we introduced are variables differently
makes more sense than what I got
hey that is 12 right not 15?
ok i have discussed this problem with others and they also agree there are no such integers i'm just shocked they would have given you a problem that you cannot find the solution to so just say there are no such integers
ok thank you