anonymous
  • anonymous
Find 3 consecutive even integers such that the square of the largest exceeds the sum of the quarters of the squares of the other two by 12
Mathematics
chestercat
  • chestercat
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mathteacher1729
  • mathteacher1729
Wow, this is a complex statement. How do you feel with simpler problems of this nature? "The sum of three consecutive integers is 12" for example. or "The sum of two consecutive odd numbers is 16" There is quite a bit to break apart in this prob, that's why I ask.
anonymous
  • anonymous
I am lost on integers
mathteacher1729
  • mathteacher1729
Oh, ok. Then any explanation of this problem will probably seem way too confusing. Let's start with the ones I wrote instead. Those are a bit simpler, and will help build up to this problem.

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mathteacher1729
  • mathteacher1729
An integer is a kind of number. It's a whole number which can be positive or negative. Also, zero is an integer. ... -3 , -2, -1, 0, 1, 2, 3, ... are all integers.
mathteacher1729
  • mathteacher1729
Do you know what "consecutive" means?
anonymous
  • anonymous
yes in a row ie 12 13 14
myininaya
  • myininaya
x is the first even integer x+2 is the next even integer x+4 is the third even integer (x+4)^2=1/4*(x^2+(x+2)^2)+12
myininaya
  • myininaya
x^2+8x+16=1/4*(x^2+x^2+4x+4)+12 x^2+8x+16=1/4*(2x^2+4x+4)+12 x^2+8x+16=x^2/2+x+1+12 x^2+8x+16=x^2/2+x+13 -x^2/2+7x+3=0 x^2-14x-6=0 this does not give us integer so maybe i misread the question
anonymous
  • anonymous
To me it seems many of these questions are not well written which doesn't help
myininaya
  • myininaya
the question seems really confusing lol
anonymous
  • anonymous
lol tell me about it. They are ALL that way
mathteacher1729
  • mathteacher1729
Myininaya -- what if we start with x = 1 :-p You need to do 2n , 2n+2 , 2n+4. Also, this is a complex problem. Is this a test or HW question?
mathteacher1729
  • mathteacher1729
It drives me mad when profs put questions on the test which are WAY MORE DIFFICULT and NOTHING LIKE the HW problems they assign or the problems they go over in class.
anonymous
  • anonymous
yeah, thanks for help. Is homework
myininaya
  • myininaya
it doesn't matter what kindof question this is this is an algebra class lol this is ridiculous for an algebra class
anonymous
  • anonymous
THANK YOU!!! I agree
myininaya
  • myininaya
unless it is a bonus question
mathteacher1729
  • mathteacher1729
Well in the proper context, it's not a ridiculous question. If this was a question at the end of the chapter on how to interpret word problems for an advanced algebra class, yeah it makes sense. Is this a TYPICAL hw problem? Like, are all the others similar in complexity to it?
anonymous
  • anonymous
This is PRE algebra. They are all this way
anonymous
  • anonymous
and not a bonus question regular one
myininaya
  • myininaya
i haven't gave up yet you wrote the question exactly as it appears in the book right?
anonymous
  • anonymous
yes
myininaya
  • myininaya
others or other?
myininaya
  • myininaya
nvm
anonymous
  • anonymous
I cant wait for this class to be over
myininaya
  • myininaya
i don't see how it isn't (x+4)^2=1/4*x^2+1/4*(x+2)^2+12 x^2+8x+16=1/4*x^2+1/4*(x^2+4x+4)+12 x^2+8x+16=1/4*x^2+1/4*x^2+x+1+12 x^2+8x+16=1/2*x^2+x+13 1/2*x^2+7x+3=0 x^2+14x+6=0 but like i said before this does not give an integer for x so i just don't get the question i guess mathteacher will you please tell me what is wrong with this
anonymous
  • anonymous
I appreciate your help
myininaya
  • myininaya
i tried lol i can't see this problem any other way what i have above is what it means to me maybe i'm making a mistake in the translation, but i don't see where or how so sorry
anonymous
  • anonymous
No need to be sorry, I appreciate it.
mathteacher1729
  • mathteacher1729
Ok, got something, but I think there might be an issue with the wording here. Lemmie know what you think.
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myininaya
  • myininaya
that is exactly how i set my up exept we introduced are variables differently
anonymous
  • anonymous
makes more sense than what I got
myininaya
  • myininaya
hey that is 12 right not 15?
anonymous
  • anonymous
yes
myininaya
  • myininaya
ok i have discussed this problem with others and they also agree there are no such integers i'm just shocked they would have given you a problem that you cannot find the solution to so just say there are no such integers
anonymous
  • anonymous
ok thank you

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