And you WANT another problem?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

And you WANT another problem?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Let me attach the one I am doing now that doesn't have an answer attached to it.
now that I know what im looking at yes lol
1 Attachment

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

thats the exact same one; only with a sqrt7 lol
ok, there you go. Let me try to work it too and see what I come up with and then you can let me know where I'VE SCREWED UP
I know it's the same one basically, but it doesn't matter, cuz I keep getting them wrong consistently!
cheat like crazy: use the computer.
we know the integral goes to \[s+s^{-1/2}\] tho so thats a start
43 to go!
when we use the bottom limit we get: \[1-2 = -1 right?\]
\[s -2s^{-1/2}\] i meant to type
\[s - \frac{2}{\sqrt{s}}+1 \rightarrow s=\sqrt{7}\] is?
\[\sqrt{7} -\frac{2}{\sqrt[4]{7}}+1\]
essentally its just: \[F(\sqrt{7})-F(1)\] \[F(s) = s-{2\over\sqrt{s}}\]
ok, you went WAYYYYYY too fast for me! I just got F(x)! Let me work this and see if I can get what you got, ok?
ok.....
i just successfully got sqrt7 - 2/ 4th root 7 for F(sqrt7). That's where I am in the figuring. Now for F(1)...
yay!!
and for shorthand: 4rt(7) is easier to read thru
ok, then here's my answer: Let me get the equation thing and do it that way.
\[\sqrt{7}-2/\sqrt[4]{7}+1\]
thats it
Is that right?
YAY!!! Couldn't have done it without you! Did I tell you I have been working on this particular problem (#31) since noon today?
yeah, :)
lets try one that is not 'exactly' the same lol
ok, so does this mean, now that you have taught me how to send you my problems, that you are willing to look at any of them I cannot do on my own (as long as you are online and available with the time?)?
yeah, ow that i aint gotta read your mind it should be easier ;)
That particular problem will have all the same types with the same integrand. That's the point, to let ua do the same ones over and over to get the precise idea of how top do them. I will see if the next problem is different and let you know, ok?
interactmath.com is just like your math program except its free. you can practice on it all you like.
1 Attachment
http://interactmath.com/PlayerPractice.aspx?bookId=92382&chapterId=6§ionId=1&exerciseId=656&type=3

Not the answer you are looking for?

Search for more explanations.

Ask your own question