And you WANT another problem?

- anonymous

And you WANT another problem?

- Stacey Warren - Expert brainly.com

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- jamiebookeater

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- anonymous

Let me attach the one I am doing now that doesn't have an answer attached to it.

- amistre64

now that I know what im looking at yes lol

- anonymous

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## More answers

- amistre64

thats the exact same one; only with a sqrt7 lol

- anonymous

ok, there you go. Let me try to work it too and see what I come up with and then you can let me know where I'VE SCREWED UP

- anonymous

I know it's the same one basically, but it doesn't matter, cuz I keep getting them wrong consistently!

- anonymous

cheat like crazy: use the computer.

- amistre64

we know the integral goes to \[s+s^{-1/2}\] tho so thats a start

- anonymous

43 to go!

- amistre64

when we use the bottom limit we get:
\[1-2 = -1 right?\]

- amistre64

\[s -2s^{-1/2}\] i meant to type

- amistre64

\[s - \frac{2}{\sqrt{s}}+1 \rightarrow s=\sqrt{7}\] is?

- amistre64

\[\sqrt{7} -\frac{2}{\sqrt[4]{7}}+1\]

- amistre64

essentally its just:
\[F(\sqrt{7})-F(1)\]
\[F(s) = s-{2\over\sqrt{s}}\]

- anonymous

ok, you went WAYYYYYY too fast for me! I just got F(x)! Let me work this and see if I can get what you got, ok?

- amistre64

ok.....

- anonymous

i just successfully got sqrt7 - 2/ 4th root 7 for F(sqrt7). That's where I am in the figuring. Now for F(1)...

- amistre64

yay!!

- amistre64

and for shorthand:
4rt(7) is easier to read thru

- anonymous

ok, then here's my answer: Let me get the equation thing and do it that way.

- anonymous

\[\sqrt{7}-2/\sqrt[4]{7}+1\]

- amistre64

thats it

- anonymous

Is that right?

- anonymous

YAY!!! Couldn't have done it without you! Did I tell you I have been working on this particular problem (#31) since noon today?

- amistre64

yeah, :)

- amistre64

lets try one that is not 'exactly' the same lol

- anonymous

ok, so does this mean, now that you have taught me how to send you my problems, that you are willing to look at any of them I cannot do on my own (as long as you are online and available with the time?)?

- amistre64

yeah, ow that i aint gotta read your mind it should be easier ;)

- anonymous

That particular problem will have all the same types with the same integrand. That's the point, to let ua do the same ones over and over to get the precise idea of how top do them. I will see if the next problem is different and let you know, ok?

- amistre64

interactmath.com is just like your math program except its free.
you can practice on it all you like.

##### 1 Attachment

- amistre64

http://interactmath.com/PlayerPractice.aspx?bookId=92382&chapterId=6§ionId=1&exerciseId=656&type=3

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