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Graph them individually in a calculator, you would see that the ln x dominates and bends the x
oh okay wait are you still here? can we discuss this more?
can you be more specific about it "bends the x" and we need to talk specific portions of the graph so when x < 0 and when x>0 what happens i think
I'll have do look this up, see if i have any info in old notes.
find anything? :)
You have to plug in x values it would give you clues. X values less than zero undefined and negative denominator x --> tends to zero. Do same process other direction.
wait let me see if I understand so when x < 0 all values are undefined, when x > 0 though..
All ln values, the denominator is defined.
when x < 0 on my calculator's table it just says ERROR
Yes, laws of log. Log equal to or greater than zero
it looks like after a certain point it pulls the graph down and keeps it close to the x axis compared to just plain y=ln(x)
Effect of smaller ln x values divided by larger x values in denominator.
right, ok now im going to type my teacher's example she gave us and we can try to mimick she explained for y=e^(x)+x that when x < 0 the graph of the function is closer to the x part of the function. This is because as x gets more and more negative, e^(x) gets smaller and samller and the function gets closer to x. When x>0 the graph is closer to the e^(x) [art f the function because as x approaches inifinity, e^(x) becomes much larger than x so the graph acts like the e^(x) part.
Best explanation, I can think of, on the bottom half of the graph it tends to zero because ln x can not be less than zero, points downward due to negative numbers in denominator. Top half, very small values of x divided by very large values of x tends to zero along the y axis to positive infinity.