anonymous
  • anonymous
how do u find the exact value of the expression: tan inverse[tan(-pi/4)]?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
arctan(tan(x))=x You're undoing what tan does to x. So here it would be -Pi/4
anonymous
  • anonymous
not... tan−1(tanx)=x only for x (−π/2,π/2)
anonymous
  • anonymous
I'm just asking

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anonymous
  • anonymous
i thought its -pi/2 please explain
anonymous
  • anonymous
tan(x)=y/x tan(-Pi/4)=-1/1=-1 arctan(x) means tangent of what angle gives x? arctan(-1)=-Pi/4, or also 3Pi/4 is a solution
anonymous
  • anonymous
shouldve said tan(theta)=y/x

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